Pollak E, Sabran M
Department of Statistics, Iowa State University, Ames 50011-1210, USA.
Math Biosci. 1999 Jul;159(2):97-112. doi: 10.1016/s0025-5564(99)00025-5.
Consider a large population with two loci that may be linked, with one having alleles A and a and the second alleles B and b. Let there be initially one individual with genotype AB/ab in a population otherwise consisting of ab/ab individuals. We assume that AB/ab, Ab/aB, AB/aB, AB/Ab and AB/AB individuals have higher probabilities of survival to adulthood than individuals with genotype ab/ab. The probability that AB ultimately survives, if there is a positive probability of selfing, is calculated. To simplify calculations, it is assumed that the number of offspring produced by any individual follows a Poisson distribution and that genotypes of separate offspring are independent. If recombination is possible, we conclude that a population with a high probability of selfing is more likely to accumulate epistatically favorable genes than one reproducing largely by random mating. This advantage of selfing becomes more pronounced as the strength of selection in favor of AB increases.
考虑一个大群体，其中有两个可能连锁的基因座，一个基因座有等位基因A和a，另一个有等位基因B和b。最初群体中除了一个基因型为AB/ab的个体外，其余个体均为ab/ab基因型。我们假设基因型为AB/ab、Ab/aB、AB/aB、AB/Ab和AB/AB的个体比基因型为ab/ab的个体有更高的成年存活率。如果存在自交的正概率，计算AB最终存活的概率。为了简化计算，假设任何个体产生的后代数量服从泊松分布，且各个后代的基因型相互独立。如果可能发生重组，我们得出结论，自交概率高的群体比主要通过随机交配繁殖的群体更有可能积累上位性有利基因。随着有利于AB的选择强度增加，自交的这种优势变得更加明显。
