Fournier Pierre-Edouard, Dumler J Stephen, Greub Gilbert, Zhang Jianzhi, Wu Yimin, Raoult Didier
Unité des Rickettsies, IFR 48, CNRS UMR 6020, Faculté de Médecine, Université de la Méditerranée, 13385 Marseille cedex 05, France.
J Clin Microbiol. 2003 Dec;41(12):5456-65. doi: 10.1128/JCM.41.12.5456-5465.2003.
We propose genetic guidelines for the classification of rickettsial isolates at the genus, group, and species levels by using sequences of the 16S rRNA (rrs) gene and four protein-coding genes, the gltA, ompA, and ompB genes and gene D. To be classified as a member of the genus Rickettsia, an isolate should exhibit degrees of rrs and gltA homology with any of the 20 Rickettsia species studied of >/=98.1 and >/=86.5%, respectively. A member of the typhus group should fulfill at least two of the following four criteria: pairwise nucleotide sequence homologies with rrs, gltA, ompB, and gene D of either Rickettsia typhi or Rickettsia prowazekii of >/=99.4, >/=96.6, >/=92.4, and >/=91.6%, respectively. A member of the spotted fever group should either possess the ompA gene or fulfill at least two of the following four criteria: pairwise nucleotide sequence homologies with rrs, gltA, ompB, and gene D of any member of this group of >/=98.8, >/=92.7, >/=85.8, and >/=82.2%, respectively. The existence of a distinct "ancestral" group should be questioned. To be classified as a new Rickettsia species, an isolate should not exhibit more than one of the following degrees of nucleotide similarity with the most homologous validated species: >/=99.8 and >/=99.9% for the rrs and gltA genes, respectively, and, when amplifiable, >/=98.8, >/=99.2, and >/=99.3% for the ompA and ompB genes and gene D, respectively. By use of our classification scheme, "Rickettsia heilongjiangii" belongs to a new species for which we officially propose the name Rickettsia heilongjiangensis sp. nov.
我们提出了基于16S rRNA(rrs)基因以及四个蛋白质编码基因(gltA、ompA、ompB基因和基因D)序列,在属、群和种水平上对立克次氏体分离株进行分类的遗传学准则。若要被归类为立克次氏体属的成员,分离株与所研究的20种立克次氏体物种中任意一种的rrs和gltA同源性程度应分别≥98.1%和≥86.5%。斑疹伤寒群的成员应至少满足以下四条标准中的两条:与鼠型斑疹伤寒立克次氏体或普氏立克次氏体的rrs、gltA、ompB和基因D的成对核苷酸序列同源性分别≥99.4%、≥96.6%、≥92.4%和≥91.6%。应质疑是否存在一个独特的“祖先”群。若要被归类为一个新的立克次氏体物种,分离株与同源性最高的已验证物种的核苷酸相似性程度不应超过以下标准:rrs和gltA基因分别为≥99.8%和≥99.9%,当可扩增时,ompA、ompB基因和基因D分别为≥98.8%、≥99.2%和≥99.3%。根据我们的分类方案,“黑龙江立克次氏体”属于一个新物种,我们正式提议将其命名为黑龙江立克次氏体新种(Rickettsia heilongjiangensis sp. nov.)。