Institute of Bioinformatics and Systems Biology, National Chiao Tung University, HsinChu 30050, Taiwan, Republic of China.
Proteins. 2013 Jul;81(7):1192-9. doi: 10.1002/prot.24268. Epub 2013 Apr 10.
We have recently showed that the weighted contact number profiles (or the packing density profiles) of proteins are well correlated with those of the corresponding sequence conservation profiles. The results suggest that a protein structure may contain sufficient information about sequence conservation comparable to that derived from multiple homologous sequences. However, there are ambiguities concerning how to compute the packing density of the subunit of a protein complex. For the subunits of a complex, there are different ways to compute its packing density--one including the packing contributions of the other subunits and the other one excluding their contributions. Here we selected two sets of enzyme complexes. Set A contains complexes with the active sites comprising residues from multiple subunits, while set B contains those with the active sites residing on single subunits. In Set A, if the packing density profile of a subunit is computed considering the contributions of the other subunits of the complex, it will agree better with the sequence conservation profile. But in Set B the situations are reversed. The results may be due to the stronger functional and structural constraints on the evolution processes on the complexes of Set A than those of Set B to maintain the enzymatic functions of the complexes. The comparison of the packing density and the sequence conservation profiles may provide a simple yet potentially useful way to understanding the structural and evolutionary couplings between the subunits of protein complexes.
我们最近表明,蛋白质的加权接触数分布(或堆积密度分布)与相应的序列保守性分布密切相关。结果表明,蛋白质结构可能包含足够的序列保守性信息,与从多个同源序列中得出的信息相当。然而,关于如何计算蛋白质复合物亚基的堆积密度仍存在一些不确定性。对于复合物的亚基,有两种不同的方法来计算其堆积密度——一种包括其他亚基的堆积贡献,另一种则排除它们的贡献。在这里,我们选择了两组酶复合物。集合 A 包含活性位点由多个亚基的残基组成的复合物,而集合 B 则包含活性位点位于单个亚基上的复合物。在集合 A 中,如果考虑复合物的其他亚基的贡献来计算一个亚基的堆积密度分布,它将与序列保守性分布更吻合。但在集合 B 中情况则相反。这一结果可能是由于集合 A 中复合物的进化过程受到更强的功能和结构限制,以维持复合物的酶活性,而集合 B 则没有这种限制。堆积密度和序列保守性分布的比较可能提供了一种简单而又有用的方法,来理解蛋白质复合物亚基之间的结构和进化耦合。