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纤维素膜上肠道病毒的浓度

Enterovirus concentration on cellulose membranes.

作者信息

Wallis C, Henderson M, Melnick J L

出版信息

Appl Microbiol. 1972 Mar;23(3):476-80. doi: 10.1128/am.23.3.476-480.1972.

Abstract

Cellulose nitrate membranes were used as one of the adsorbents in concentrating viruses from water. For adsorption to occur, salts were required. With increase in valency of salt, less salt was necessary for enhanced virus adsorption to membranes. Trivalent salts were more effective because they could be used at only 1% the concentration required for divalent salts. Thus, 0.5 mM AlCl(3) was as effective as 50 mM MgCl(2). For testing 500 gal of water, only 0.24 kg of AlCl(3) was required in contrast to 20 kg of MgCl(2). Virus could then be eluted from such membranes, having an area of 486 cm(2), with 250 ml of pH 11.5 buffer. Lowering the pH of the eluate and adding AlCl(3) permitted the virus to be quickly readsorbed on a smaller cellulose membrane, i.e., 4 cm(2). Virus for assay was eluted from the small membrane in 1 ml. This procedure has provided the basis for concentrating minute amounts of virus from large volumes of water.

摘要

硝酸纤维素膜被用作从水中浓缩病毒的吸附剂之一。为了发生吸附作用,需要盐类。随着盐价态的增加,增强病毒对膜的吸附所需的盐量减少。三价盐更有效,因为它们的使用浓度仅为二价盐所需浓度的1%。因此,0.5 mM的AlCl₃与50 mM的MgCl₂效果相同。对于检测500加仑的水,仅需要0.24千克的AlCl₃,而MgCl₂则需要20千克。然后可以用250毫升pH 11.5的缓冲液从面积为486平方厘米的这种膜上洗脱病毒。降低洗脱液的pH值并添加AlCl₃可使病毒快速重新吸附在较小的纤维素膜上,即4平方厘米的膜上。用于检测的病毒用1毫升从小膜上洗脱下来。该程序为从大量水中浓缩微量病毒提供了基础。

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