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钴-4,4'-联苯二甲酸配位聚合物的反应及反应活性(4,4'-联苯二甲酸即bpdc)

Reactions and reactivity of Co-bpdc coordination polymers (bpdc = 4,4'-biphenyldicarboxylate).

作者信息

Pan L, Ching N, Huang X, Li J

机构信息

Department of Chemistry, Rutgers University, Camden, New Jersey 08102, USA.

出版信息

Inorg Chem. 2000 Nov 13;39(23):5333-40. doi: 10.1021/ic0004939.

Abstract

By choosing a suitable metal center, ligand, and solvents, we have revealed several structural transformations involving a polymer precursor. infinity 1[Co(bpdc)(H2O)2].H2O (1) was prepared by reaction of Na2bpdc and Co(NO3)2 in aqueous solution. Immersing 1 in pyridine/water solutions of (2:1) and (8:1) ratios yielded a second one-dimensional structure infinity 1[Co(bpdc)(py)2(H2O)2].2py (2) and a two-dimensional structure infinity 2[Co(bpdc)(py)2].H2O (3), respectively. After heating 1 under N2 to remove all water within the structure, the compound Co(bpdc) (IR) was obtained. When IR was immersed in solutions of pyridine/water (5:4) and in pure pyridine (in air), a third one-dimensional structure of infinity 1[Co(bpdc)(py)2(H2O)2].2py.H2O (4) and 3, respectively, were obtained. Compounds 2-4 easily transformed to 1 when immersed in water. Crystal data for 1: monoclinic, space group C2/c with a = 6.950(1), b = 31.585(6), and c = 6.226(1) A, beta = 95.84(3) degrees, Z = 4. Crystal data for 2: triclinic, space group P1 with a = 9.646(2), b = 10.352(2), and c = 17.031(3) A, alpha = 79.02(3) degrees, beta = 86.88(3) degrees, gamma = 77.16(3) degrees, Z = 2. Crystal data for 3: triclinic, space group P1 with a = 9.137(2), b = 10.480(2), and c = 12.254(2) A, alpha = 102.10(3) degrees, beta = 100.80(3) degrees, gamma = 99.43(3) degrees, Z = 2. Crystal data for 4: orthorhombic, space group Pbcn with a = 13.468(3), b = 16.652 (3), and c = 14.977(3) A, Z = 4.

摘要

通过选择合适的金属中心、配体和溶剂,我们揭示了几种涉及聚合物前体的结构转变。通过在水溶液中使Na2bpdc与Co(NO3)2反应制备了infinity 1[Co(bpdc)(H2O)2].H2O (1)。将1浸入比例为(2:1)和(8:1)的吡啶/水溶液中,分别得到了第二种一维结构infinity 1[Co(bpdc)(py)2(H2O)2].2py (2)和二维结构infinity 2[Co(bpdc)(py)2].H2O (3)。在N2气氛下加热1以除去结构内的所有水后,得到化合物Co(bpdc) (IR)。当IR浸入吡啶/水(5:4)溶液和纯吡啶(在空气中)中时,分别得到了第三种一维结构infinity 1[Co(bpdc)(py)2(H2O)2].2py.H2O (4)和3。将化合物2 - 4浸入水中时很容易转变为1。1的晶体数据:单斜晶系,空间群C2/c,a = 6.950(1),b = 31.585(6),c = 6.226(1) Å,β = 95.84(3)°,Z = 4。2的晶体数据:三斜晶系,空间群P1,a = 9.646(2),b = 10.352(2),c = 17.031(3) Å,α = 79.02(3)°,β = 86.88(3)°,γ = 77.16(3)°,Z = 2。3的晶体数据:三斜晶系,空间群P1,a = 9.137(2),b = 10.480(2),c = 12.254(2) Å,α = 102.10(3)°,β = 100.80(3)°,γ = 99.43(3)°,Z = 2。4的晶体数据:正交晶系,空间群Pbcn,a = 13.468(3),b = 16.652 (3),c = 14.977(3) Å,Z = 4。

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