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四配位平面RuII。三重态作为对14价电子构型的响应。

Four-coordinate, planar RuII. A triplet state as a response to a 14-valence electron configuration.

作者信息

Watson Lori A, Ozerov Oleg V, Pink Maren, Caulton Kenneth G

机构信息

Department of Chemistry and Molecular Structure Center, Indiana University, Bloomington, Indiana 47405, USA.

出版信息

J Am Chem Soc. 2003 Jul 16;125(28):8426-7. doi: 10.1021/ja035166p.

Abstract

The ligand (tBu2PCH2SiMe2)2N1- (PNP) in [PNP]RuCl leads to an intermediate spin ground state, S = 1, which has been characterized by NMR and X-ray diffraction as having a planar structure. This spin state is attributed in part to N --> Ru pi donation. DFT calculations confirm that the singlet state lies higher in energy and is nonplanar. The molecule is converted to a diamagnetic product by addition of 2 mol of PhCN. The half-filled orbitals of the S = 1 state are suggested to be the reason agostic interactions do not compensate for the 14-valence electron count.

摘要

[PNP]RuCl中的配体(tBu2PCH2SiMe2)2N1-(PNP)导致中间自旋基态,S = 1,通过核磁共振和X射线衍射表征为具有平面结构。这种自旋态部分归因于N→Ru π电子给予。密度泛函理论计算证实单重态能量更高且为非平面结构。通过加入2摩尔苯甲腈,该分子转化为抗磁性产物。S = 1态的半充满轨道被认为是σ-键合相互作用不能补偿14价电子数的原因。

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