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关于异丙醇铝对原子转移自由基聚合以及对催化剂-休眠链卤素交换影响的实验与计算研究

An experimental and computational study on the effect of Al(OiPr)3 on atom-transfer radical polymerization and on the catalyst-dormant-chain halogen exchange.

作者信息

Poli Rinaldo, Stoffelbach François, Maria Sébastien, Mata José

机构信息

Laboratoire de Chimie de Coordination, UPR CNRS 8241, 205 Route de Narbonne, 31077 Toulouse Cedex, France.

出版信息

Chemistry. 2005 Apr 8;11(8):2537-48. doi: 10.1002/chem.200401143.

Abstract

Compound Al(OiPr)3 is shown to catalyze the halide-exchange process leading from [Mo(Cp)Cl2(iPrN=CH-CH=NiPr)] and CH3CH(X)COOEt (X=Br, I) to the mixed-halide complexes [Mo(Cp)ClX(iPrN=CH-CH=NiPr)]. On the other hand, no significant acceleration is observed for the related exchange between [MoX3(PMe3)3] (X=Cl, I) and PhCH(Br)CH3, by analogy to a previous report dealing with the Ru(II) complex [RuCl2(PPh3)3]. A DFT computation study, carried out on the model complexes [Mo(Cp)Cl2(PH3)2], [MoCl3(PH3)3], and [RuCl2(PH3)3], and on the model initiators CH3CH(Cl)COOCH3, CH3Cl, and CH3Br, reveals that the 16-electron Ru(II) complex is able to coordinate the organic halide RX in a slightly exothermic process to yield saturated, diamagnetic [RuCl2(PH3)3(RX)] adducts. The 15-electron [MoCl3(PH3)3] complex is equally capable of forming an adduct, that is, the 17-electron [MoCl3(PH3)3(CH3Cl)] complex with a spin doublet configuration, although the process is endothermic, because it requires an energetically costly electron-pairing process. The interaction between the 17-electron [Mo(Cp)Cl2(PH3)2] complex and CH3Cl, on the other hand, is repulsive and does not lead to a stable 19-electron adduct. The [RuCl2(PH3)3(CH3X)] system leads to an isomeric complex [RuClX(PH3)3(CH3Cl)] by internal nucleophilic substitution at the carbon atom. The transition state of this process for X=Cl (degenerate exchange) is located at lower energy than the transition state required for halogen-atom transfer leading to [RuCl3(PH3)3] and the free radical CH3. On the basis of these results, the uncatalyzed halide exchange is interpreted as the result of a competitive S(N)i process, whose feasibility depends on the electronic configuration of the transition-metal complex. The catalytic action of Al(OiPr)3 on atom-transfer radical polymerization (and on halide exchange for the 17-electron half-sandwich Mo(III) complex) results from a more favorable Lewis acid-base interaction with the oxidized metal complex, in which the transferred halogen atom is bound to a more electropositive element. This conclusion derives from DFT studies of the model [Al(OCH3)3]n (n=1,2,3,4) compounds, and on the interaction of Al(OCH3)3 with CH3Cl and with the [Mo(Cp)Cl3(PH3)2] and [RuCl3(PH3)3] complexes.

摘要

已表明化合物Al(OiPr)₃能催化卤化物交换过程,该过程从[Mo(Cp)Cl₂(iPrN=CH-CH=NiPr)]和CH₃CH(X)COOEt(X = Br、I)生成混合卤化物配合物[Mo(Cp)ClX(iPrN=CH-CH=NiPr)]。另一方面,与之前关于Ru(II)配合物[RuCl₂(PPh₃)₃]的报道类似,未观察到[MoX₃(PMe₃)₃](X = Cl、I)与PhCH(Br)CH₃之间的相关交换有显著加速。对模型配合物[Mo(Cp)Cl₂(PH₃)₂]、[MoCl₃(PH₃)₃]和[RuCl₂(PH₃)₃]以及模型引发剂CH₃CH(Cl)COOCH₃、CH₃Cl和CH₃Br进行的密度泛函理论(DFT)计算研究表明,16电子的Ru(II)配合物能够在一个轻微放热的过程中与有机卤化物RX配位,生成饱和、抗磁性的[RuCl₂(PH₃)₃(RX)]加合物。15电子的[MoCl₃(PH₃)₃]配合物同样能够形成加合物,即具有自旋双重态构型的17电子[MoCl₃(PH₃)₃(CH₃Cl)]配合物,尽管该过程是吸热的,因为它需要一个能量成本高昂的电子配对过程。另一方面,17电子的[Mo(Cp)Cl₂(PH₃)₂]配合物与CH₃Cl之间的相互作用是排斥性的,不会形成稳定的19电子加合物。[RuCl₂(PH₃)₃(CH₃X)]体系通过碳原子上的分子内亲核取代生成异构体配合物[RuClX(PH₃)₃(CH₃Cl)]。对于X = Cl(简并交换),该过程的过渡态能量低于生成[RuCl₃(PH₃)₃]和自由基CH₃所需的卤原子转移的过渡态能量。基于这些结果,未催化的卤化物交换被解释为竞争性S(N)i过程的结果,其可行性取决于过渡金属配合物的电子构型。Al(OiPr)₃对原子转移自由基聚合(以及对17电子半夹心Mo(III)配合物的卤化物交换)的催化作用源于与氧化态金属配合物更有利的路易斯酸碱相互作用,其中转移的卤原子与一个电正性更强的元素结合。这一结论来自对模型[Al(OCH₃)₃]ₙ(n = 1、2、3、4)化合物以及Al(OCH₃)₃与CH₃Cl以及与[Mo(Cp)Cl₃(PH₃)₂]和[RuCl₃(PH₃)₃]配合物相互作用的DFT研究。

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