Lührs Thorsten, Ritter Christiane, Adrian Marc, Riek-Loher Dominique, Bohrmann Bernd, Döbeli Heinz, Schubert David, Riek Roland
The Salk Institute for Biological Studies, La Jolla, CA 92037, USA.
Proc Natl Acad Sci U S A. 2005 Nov 29;102(48):17342-7. doi: 10.1073/pnas.0506723102. Epub 2005 Nov 17.
Alzheimer's disease is the most fatal neurodegenerative disorder wherein the process of amyloid-beta (Abeta) amyloidogenesis appears causative. Here, we present the 3D structure of the fibrils comprising Abeta(1-42), which was obtained by using hydrogen-bonding constraints from quenched hydrogen/deuterium-exchange NMR, side-chain packing constraints from pairwise mutagenesis studies, and parallel, in-register beta-sheet arrangement from previous solid-state NMR studies. Although residues 1-17 are disordered, residues 18-42 form a beta-strand-turn-beta-strand motif that contains two intermolecular, parallel, in-register beta-sheets that are formed by residues 18-26 (beta1) and 31-42 (beta2). At least two molecules of Abeta(1-42) are required to achieve the repeating structure of a protofilament. Intermolecular side-chain contacts are formed between the odd-numbered residues of strand beta1 of the nth molecule and the even-numbered residues of strand beta2 of the (n - 1)th molecule. This interaction pattern leads to partially unpaired beta-strands at the fibrillar ends, which explains the sequence selectivity, the cooperativity, and the apparent unidirectionality of Abeta fibril growth. It also provides a structural basis for fibrillization inhibitors.
阿尔茨海默病是最致命的神经退行性疾病,其中β-淀粉样蛋白(Aβ)的淀粉样蛋白生成过程似乎是致病原因。在此,我们展示了由Aβ(1-42)组成的纤维的三维结构,该结构是通过利用淬灭氢/氘交换核磁共振的氢键限制、成对诱变研究的侧链堆积限制以及先前固态核磁共振研究的平行、对齐β-折叠排列获得的。尽管1-17位残基无序,但18-42位残基形成了一个β-链-转角-β-链基序,其中包含两个由18-26位残基(β1)和31-42位残基(β2)形成的分子间平行、对齐β-折叠。至少需要两个Aβ(1-42)分子才能实现原纤维的重复结构。在第n个分子的β1链奇数位残基与第(n - 1)个分子的β2链偶数位残基之间形成分子间侧链接触。这种相互作用模式导致纤维末端部分未配对的β-链,这解释了Aβ纤维生长的序列选择性、协同性和明显的单向性。它还为纤维化抑制剂提供了结构基础。