Muktha B, Guru Row T N
Solid State and Structural Chemistry Unit, Indian Institute of Science, Bangalore 560012, India.
Inorg Chem. 2006 Jun 12;45(12):4706-11. doi: 10.1021/ic0601337.
Two new phosphates, Bi(4.25)(PO4)2O(3.375) and Bi(5)(PO(4))(2)O(4.5), have been analyzed by single-crystal X-ray diffraction in the series Bi(4+x)(PO4)2O(3+3x/2) (0.175 < or = x < or = 1). The syntheses of the compositions ranging from x = 0.175 to 0.475 were carried out by the ceramic route. The compositions from x = 0.175 to 0.475 form a solid solution with a structure similar to that of Bi(4.25)(PO4)2O(3.375), while Bi(5)(PO4)2O(4.5) was isolated from a mixture of two phases. Both of the phases form fluorite-related structures but, nevertheless, differ from each other with respect to the arrangement of the bismuth atoms. The uniqueness in the structures is the appearance of isolated PO(4) tetrahedra separated by interleaving [Bi2O2] units. ac impedance studies indicate conductivity on the order of 10(-5) S cm(-1) for Bi(4.25)(PO4)2O(3.375). Crystal data: Bi(4.25)(PO4)2O(3.375), triclinic, space group P (No. 1), with a = 7.047(1) A, b = 9.863(2) A, c = 15.365(4) A, alpha = 77.604(4) degrees, beta = 84.556(4) degrees, gamma = 70.152(4) degrees, V = 980.90(4) A3, and Z = 4; Bi(5)(PO4)2O(4.5), monoclinic, space group C2/c (No. 15), with a = 13.093(1) A, b = 5.707(1) A, c = 15.293(1) A, beta = 98.240(2) degrees, V = 1130.95(4) A(3), and Z = 8.
通过单晶X射线衍射对系列Bi(4+x)(PO4)2O(3+3x/2)(0.175≤x≤1)中的两种新型磷酸盐Bi(4.25)(PO4)2O(3.375)和Bi(5)(PO4)2O(4.5)进行了分析。x值从0.175到0.475的组合物通过陶瓷法合成。x值从0.175到0.475的组合物形成一种固溶体,其结构与Bi(4.25)(PO4)2O(3.375)的结构相似,而Bi(5)(PO4)2O(4.5)是从两相混合物中分离出来的。这两种相都形成与萤石相关的结构,然而,它们在铋原子的排列方面彼此不同。结构中的独特之处在于出现了由交错的[Bi2O2]单元隔开的孤立PO4四面体。交流阻抗研究表明Bi(4.25)(PO4)2O(3.375)的电导率约为10^(-5) S cm^(-1)。晶体数据:Bi(4.25)(PO4)2O(3.375),三斜晶系,空间群P(编号1),a = 7.047(1) Å,b = 9.863(2) Å,c = 15.365(4) Å,α = 77.604(4)°,β = 84.556(4)°,γ = 70.152(4)°,V = 980.90(4) ų,Z = 4;Bi(5)(PO4)2O(4.5),单斜晶系,空间群C2/c(编号15),a = 13.093(1) Å,b = 5.707(1) Å,c = 15.293(1) Å,β = 98.240(2)°,V = 1130.95(4) ų,Z = 8。