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由费歇尔卡宾配合物和4-未取代的1-氨基-1,3-二烯非对映选择性合成三元、五元、六元和七元环。

Diastereoselective synthesis of three-, five-, six-, and seven-membered rings from Fischer carbene complexes and 4-unsubstituted 1-amino-1,3-dienes.

作者信息

Aznar Fernando, Fañanás-Mastral Martín, Alonso Jorge, Fañanás Francisco J

机构信息

Instituto Universitario de Química Organometálica, Enrique Moles, Unidad Asociada al CSIC, Universidad de Oviedo, Julián Clavería 8, 33006 Oviedo, Spain.

出版信息

Chemistry. 2008;14(1):325-32. doi: 10.1002/chem.200701109.

Abstract

Fischer carbene complexes react with 4-unsubstituted 1-amino-1,3-dienes to give different carbocyclization products depending on the nature of the carbene complex and on the substitution pattern of the aminodiene. Thus, the reaction of arylcarbene chromium complexes and 1-aminodienes diastereoselectively affords cyclopropane derivatives by means of a formal [2+1] carbocyclization reaction. In particular, pentacarbonyl[(2-furyl)(methoxy)methylene]chromium complex furnishes formal [4+1] carbocyclization products. Starting from beta-substituted alkenylcarbene complexes, formal [4+1] reactions occur and cyclopentenamine derivatives are diastereoselectively formed. However, when the alpha,beta-disubstituted alkenylcarbene complex pentacarbonyl[(5,6-dihydro-2H-pyran-2-yl)(methoxy)methylene]tungsten is used, the outcome of the reaction depends on the substitution on the carbon atom at the 3-position of the aminodiene, generating the [3+2] or [4+3]-cyclization products if the substituent is or is not a hydrogen atom, respectively. Finally, when the reaction is performed with alkynylcarbene complexes, benzaldehyde derivatives are obtained if the triple-bond substituent is a phenyl group or indene derivatives if the group is an alkenyl moiety.

摘要

费歇尔卡宾配合物与4-未取代的1-氨基-1,3-二烯反应,根据卡宾配合物的性质和氨基二烯的取代模式生成不同的碳环化产物。因此,芳基卡宾铬配合物与1-氨基二烯通过形式上的[2+1]碳环化反应非对映选择性地生成环丙烷衍生物。特别地,五羰基[(2-呋喃基)(甲氧基)亚甲基]铬配合物提供形式上的[4+1]碳环化产物。从β-取代的烯基卡宾配合物开始,发生形式上的[4+1]反应并非对映选择性地形成环戊烯胺衍生物。然而,当使用α,β-二取代的烯基卡宾配合物五羰基[(5,6-二氢-2H-吡喃-2-基)(甲氧基)亚甲基]钨时,反应的结果取决于氨基二烯3-位碳原子上的取代情况,如果取代基是或不是氢原子,则分别生成[3+2]或[4+3]环化产物。最后,当用炔基卡宾配合物进行反应时,如果三键取代基是苯基,则得到苯甲醛衍生物,如果该基团是烯基部分,则得到茚衍生物。

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