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乙酰胆碱是如何失去三甲胺的?四种竞争机制的密度泛函理论研究。

How does acetylcholine lose trimethylamine? A density functional theory study of four competing mechanisms.

作者信息

Lioe Hadi, Barlow Christopher K, O'Hair Richard A J

机构信息

School of Chemistry, University of Melbourne, Victoria, Australia.

出版信息

J Am Soc Mass Spectrom. 2009 Feb;20(2):238-46. doi: 10.1016/j.jasms.2008.09.017. Epub 2008 Sep 25.

DOI:10.1016/j.jasms.2008.09.017
PMID:18974009
Abstract

Low-energy collision-induced dissociation (CID) of acetylcholine (ACh) yields only two fragment ions: the dominant C(4)H(7)O(2)(+) ion at m/z 87, arising from trimethylamine loss; and protonated trimethylamine at m/z 60. Since the literature is replete with conflicting mechanisms for the loss of trimethylamine from ACh, in this article density functional theory (DFT) calculations are used to assess four competing mechanisms: (1) Path A involves a neighboring group attack to form a five-membered ring product, 2-methyl-1,3-dioxolan-2-ylium cation; (2) Path B is a neighboring group attack to form a three-membered ring product, 1-methyl-oxiranium ion; (3) Path C involves an intramolecular elimination reaction to form CO protonated vinylacetate; and (4) Path D is a 1,2-hydride migration reaction forming CH(2)-protonated vinylacetate. At the MP2/6-311++G(2d,p)//B3-LYP/6-31+G(d,p) level of theory path A is the kinetically favored pathway, with a transition-state energy barrier of 37.7 kcal mol(-1) relative to the most stable conformer of ACh. The lowest energy pathway for the formation of protonated trimethylamine was also calculated to proceed via path A, involving proton transfer within the ion-molecule complex intermediate, with the exocylic methyl group being the proton donor. To confirm the site of proton transfer, low-energy CID of acetyl-d(3)-choline (d(3)-ACh) was carried out, which revealed loss of trimethylamine and the formation of Me(3)ND(+).

摘要

乙酰胆碱(ACh)的低能碰撞诱导解离(CID)仅产生两种碎片离子:质荷比为87的主要C(4)H(7)O(2)(+)离子,由三甲胺损失产生;以及质荷比为60的质子化三甲胺。由于文献中充斥着关于ACh中三甲胺损失的相互矛盾的机制,本文使用密度泛函理论(DFT)计算来评估四种竞争机制:(1)路径A涉及邻基进攻以形成五元环产物,即2-甲基-1,3-二氧戊环-2-鎓阳离子;(2)路径B是邻基进攻以形成三元环产物,即1-甲基环氧鎓离子;(3)路径C涉及分子内消除反应以形成CO质子化的乙酸乙烯酯;(4)路径D是1,2-氢迁移反应形成CH(2)-质子化的乙酸乙烯酯。在MP2/6-311++G(2d,p)//B3-LYP/6-31+G(d,p)理论水平下,路径A是动力学上有利的途径,相对于ACh最稳定构象,其过渡态能垒为37.7 kcal mol(-1)。质子化三甲胺形成的最低能量途径也经计算是通过路径A进行的,涉及离子-分子复合中间体中的质子转移,环外甲基作为质子供体。为了确认质子转移位点,进行了乙酰-d(3)-胆碱(d(3)-ACh)的低能CID,结果显示三甲胺损失并形成Me(3)ND(+)。

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