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珠江口悬浮物质的现场和 MERIS 数据观测。

Total suspended matter observation in the Pearl River estuary from in situ and MERIS data.

机构信息

Institute of Space and Earth Information Science, Yuen Yuen Research Centre for Satellite Remote Sensing, The Chinese University of Hong Kong, Shatin, NT, Hong Kong.

出版信息

Environ Monit Assess. 2011 Jun;177(1-4):563-74. doi: 10.1007/s10661-010-1657-3. Epub 2010 Sep 1.

Abstract

Based on the cruise data collected in the Pearl River estuary (PRE) in May 2008, an empirical two-band model by using the ratio of R (rs) at 629 and 671 nm was established to retrieve total suspended matter (TSM) concentration with the determination coefficient (R(2)) of 0.854, mean relative error (MRE) of 7.483%, and root-mean-square error (RMSE) of 1.295 mg L( - 1). To match with medium resolution imaging spectrometer (MERIS) bands, in situ remote sensing reflectance was re-sampled to the bandwidth of 10 nm. The relationship between TSM and re-sampled R (rs) at 620 nm (MERIS band 6) and 665 nm (MERIS band 7) are obtained (R(2) = 0.748, RMSE = 1.697 mg L( - 1), MRE = 8.785%, n = 13). Additionally, to map the spatial distribution of TSM in the PRE, MERIS level_1B data were calibrated using a multiple linear regression model based on in situ R (rs). Another dataset collected in the PRE in January 2004 was used to validate the two-band model and also applied to map TSM distribution from MERIS image. The comparison between measured TSM values and modeled ones showed satisfactory results (R(2) = 0.753, MRE = 22.199%, and RMSE = 2.603 mg L( - 1)).

摘要

基于 2008 年 5 月在珠江口(PRE)收集的巡航数据,建立了一个使用 629 和 671nm 处的 R(rs)比值的经验双波段模型,以 0.854 的决定系数(R(2))、7.483%的平均相对误差(MRE)和 1.295mgL(-1)的均方根误差(RMSE)来反演总悬浮物浓度(TSM)。为了与中等分辨率成像光谱仪(MERIS)波段相匹配,对现场遥感反射率进行了重采样,带宽为 10nm。得到了 TSM 与重采样 R(rs)在 620nm(MERIS 波段 6)和 665nm(MERIS 波段 7)处的关系(R(2)=0.748,RMSE=1.697mgL(-1),MRE=8.785%,n=13)。此外,为了绘制 PRE 中 TSM 的空间分布,使用基于现场 R(rs)的多元线性回归模型对 MERIS level_1B 数据进行了校准。还使用 2004 年 1 月在 PRE 收集的另一个数据集来验证双波段模型,并将其应用于从 MERIS 图像中绘制 TSM 分布。实测 TSM 值与模型值的比较结果令人满意(R(2)=0.753,MRE=22.199%,RMSE=2.603mgL(-1))。

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