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使用区域选择性生成的自由基阳离子进行气相离子-分子反应,以模拟肽中的氧化损伤和探测自由基位点。

Gas-phase ion-molecule reactions using regioselectively generated radical cations to model oxidative damage and probe radical sites in peptides.

机构信息

ARC Centre of Excellence for Free Radical Chemistry and Biotechnology, Victoria, Australia.

出版信息

Org Biomol Chem. 2011 May 21;9(10):3733-45. doi: 10.1039/c0ob01245a. Epub 2011 Mar 31.

Abstract

Collision induced dissociation (CID) of sodiated peptide derivatives containing a nitrate ester functionality was used to regiospecifically generate three isomeric radicals of the model peptide Bz-Ala-Gly-OMe corresponding to radicals formed at: C(α) of the alanine residue 4+Na; C(α) of the glycine residue 5+Na; and the side chain of alanine 6+Na. The ion-molecule reactions of these peptide radicals were examined to model oxidative damage to peptides and to probe whether the radical sites maintain their integrity or whether they isomerise via intramolecular hydrogen atom transfer (HAT). Only 6+Na is reactive towards O(2), forming the peroxyl radical 7+Na, which loses O(2), HO˙ and HO(2)˙ under CID. The radical ion 7 + Na abstracts a hydrogen atom from 4-fluorothiophenol to form the hydroperoxide 8+Na, which upon CID fragments via the combined loss of HO˙ and CH(2)O. In contrast, all three of the isomeric sodiated radicals react with NO˙ and NO(2)˙ to form adducts. CID of the NO adducts only regenerates the radicals via NO˙ loss, thus providing no structural information. In contrast, CID of the NO(2) adducts gives rise to a range of product ions and the spectra are different for each of the three adducts, suggesting that the isomeric radicals 4+Na, 5+Na and 6+Na are produced as discrete species. Finally, CID of the NO(2) adducts was used to probe the rearrangement of the radicals 4+Na, 5+Na and 6+Na prior to their reaction with NO(2)˙: 6 + Na rearranges to a mixture of 4+Na and 5+Na while 5+Na rearranges to 4+Na.

摘要

利用含硝酸酯功能的加钠肽衍生物的碰撞诱导解离(CID),可以特异地生成模型肽 Bz-Ala-Gly-OMe 的三个立体异构自由基,它们分别对应于:丙氨酸残基的 Cα位[4+Na]+;甘氨酸残基的 Cα位[5+Na]+;以及丙氨酸的侧链[6+Na]+。研究了这些肽自由基的离子-分子反应,以模拟肽的氧化损伤,并探究自由基位点是否保持其完整性,或者它们是否通过分子内氢原子转移(HAT)发生异构化。只有[6+Na]+与 O2 反应,形成过氧自由基[7+Na]+,它在 CID 下失去 O2、HO˙和 HO2˙。自由基离子[7+Na]+从 4-氟噻酚中提取一个氢原子,形成过氢氧化物[8+Na]+,它在 CID 下通过共同失去 HO˙和 CH2O 片段化。相比之下,三种立体异构的加钠自由基都与 NO˙和 NO2˙反应形成加合物。NO 加合物的 CID 仅通过 NO˙的损失再生自由基,因此没有提供结构信息。相比之下,NO2 加合物的 CID 会产生一系列的产物离子,并且对于三种加合物中的每一种,其谱图都不同,这表明立体异构的自由基[4+Na]+、[5+Na]+和[6+Na]+是以离散的物种形式产生的。最后,利用 NO2 加合物的 CID 来探测自由基[4+Na]+、[5+Na]+和[6+Na]+在与 NO2˙反应之前的重排:[6+Na]+重排为[4+Na]+和[5+Na]+的混合物,而[5+Na]+重排为[4+Na]+。

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