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二水合双(N,N - 二乙基吡啶 - 3 - 甲酰胺 - κN)双{4 - [2 - (2,4 - 二氧代戊 - 3 - 亚基)肼 - 1 - 基]苯甲酸根 - κO}铜(II)

Diaqua-bis-(N,N-diethyl-pyridine-3-carboxamide-κN)bis-{4-[2-(2,4-dioxopentan-3-yl-idene)hydrazin-1-yl]benzoato-κO}copper(II).

作者信息

Alieva Rafiqa A, Mardanova Vusala I, Chyraqov Famil M, Gurbanov Atash V, Ng Seik Weng

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2012 Feb 1;68(Pt 2):m127. doi: 10.1107/S1600536811056200. Epub 2012 Jan 11.

Abstract

In the title compound, [Cu(C(12)H(11)N(2)O(4))(2)(C(10)H(14)N(2)O)(2)(H(2)O)(2)], the Cu(II) atom lies on a center of inversion and is coordinated by carboxyl-ate O atoms, pyridine N atoms and two water mol-ecules in an elongated octa-hedral geometry. The pyridine ring is oriented at a dihedral angle of 74.83 (12)° with respect to the benzene ring. Intra-molecular O-H⋯O and N-H⋯O hydrogen bonding is observed. The water mol-ecule is a hydrogen-bond donor to the carbonyl O atom of an adjacent carboxyl-ate group, generating a chain running along the a axis. One of the ethyl groups is disordered over two sets of sites in a 0.787 (5):0.213 ratio.

摘要

在标题化合物[Cu(C₁₂H₁₁N₂O₄)₂(C₁₀H₁₄N₂O)₂(H₂O)₂]中,Cu(II)原子位于对称中心,以拉长的八面体几何构型由羧酸根O原子、吡啶N原子和两个水分子配位。吡啶环相对于苯环的二面角为74.83 (12)°。观察到分子内的O—H⋯O和N—H⋯O氢键。水分子是相邻羧酸根基团羰基O原子的氢键供体,形成了沿a轴延伸的链。其中一个乙基在两组位置上无序,比例为0.787 (5):0.213。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/8ad6/3274866/57701fdac21a/e-68-0m127-fig1.jpg

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