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[过氧化氢对水混合物进行催化氧化过程中的物质平衡]

[Balance of substances during catalytic oxidation of water admixtures by hydrogen peroxide].

作者信息

Vasilenko I I, Sheve'l N M, Siniak Iu E

出版信息

Kosm Biol Aviakosm Med. 1989 Sep-Oct;23(5):75-8.

PMID:2512416
Abstract

Kinetics of CO2 and O2 production was investigated in the following systems: H2O - H2O2 - C6H5OH - siderite, H2O - H2O2 - HCl - siderite, H2O - H2O2 - siderite, H2O - HCl - siderite. A general equation describing the kinetics of phenol oxidation to yield carbon dioxide was derived: Vco2 = k2[C6H5OH]0.55 [H2O2]2 [Fe2+]2, where [Fe2+] denotes iron in the catalyst. The rate of oxygen production in the presence of phenol and siderite was described as Vo2 = k1 [H2O2]1.46. The CO2/O2 ratio in the concentration range 0.5-2.0 M H2O2 increased from 12.8 to 87.2 vol. %. The conversion degree of 0.05 M C6H5OH to carbon dioxide after 35 min oxidation in the presence of 0.5 g of the catalyst and at t = 21 degrees C reached 99.8%. As a result of chemical reactions between hydrogen of the admixtures and oxygen of the oxidizing agent as well as catalytic decomposition of hydrogen peroxide, the amount of pure water in the system increases. Due to reclamation of water containing wastes produced by one person, the total amount of additional water in space mission is estimated to make 204 kg per year.

摘要

研究了以下体系中二氧化碳和氧气的生成动力学

水 - 过氧化氢 - 苯酚 - 菱铁矿、水 - 过氧化氢 - 盐酸 - 菱铁矿、水 - 过氧化氢 - 菱铁矿、水 - 盐酸 - 菱铁矿。推导出了一个描述苯酚氧化生成二氧化碳动力学的通用方程:Vco2 = k2[C6H5OH]0.55 [H2O2]2 [Fe2+]2,其中[Fe2+]表示催化剂中的铁。在苯酚和菱铁矿存在下的氧气生成速率描述为Vo2 = k1 [H2O2]1.46。在0.5 - 2.0 M过氧化氢浓度范围内,二氧化碳/氧气的体积比从12.8%增加到87.2%。在0.5 g催化剂存在且温度t = 21摄氏度的条件下,0.05 M苯酚在氧化35分钟后转化为二氧化碳的转化率达到99.8%。由于混合物中的氢与氧化剂中的氧发生化学反应以及过氧化氢的催化分解,体系中纯水的量增加。由于回收了一个人产生的含水废物,估计太空任务中每年额外水的总量为204千克。

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