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吡哆胺与戊糖美拉德反应形成的新型亲水性化合物的分离、鉴定及形成机制的提出。

Isolation, identification, and proposed formation mechanism of a novel hydrophilic compound formed by Maillard reaction between pyridoxamine and pentose.

机构信息

Faculty of Applied Life Sciences, Niigata University of Pharmacy and Applied Life Sciences, Niigata City, Niigata, Japan.

Faculty of Human Life and Environmental Sciences, Ochanomizu university, Bunkyo-ku, Tokyo, Japan.

出版信息

Sci Rep. 2020 Feb 4;10(1):1823. doi: 10.1038/s41598-020-58727-8.

Abstract

Pyridoxamine (PM) could competitively protect amino groups in proteins from glycating agents. Although PM is expected to react with saccharides, available data therein are limited. In this study, a novel hydrophilic compound from a model reaction solution containing PM and xylose was isolated and identified as (6aR,9aR)-1,8,9-trihydroxy-2,6a-dimethyl-6a,9a-dihydrocyclopenta[5,6]pyrano[3,4-c]pyridin-7(5H)-one with a tricyclic structure. This compound appeared to be specifically formed from pentose via 1-deoxypentosone, and its formation was facilitated over a pH range of 7.0-8.0. After heating at 90 °C for 5 h in a reaction mixture containing 30 mM PM and pentose at pH 7.4, this compound was obtained at a yield of 6.95-8.53 mM.

摘要

吡哆胺 (PM) 可以竞争性地保护蛋白质中的氨基免受糖基化试剂的影响。尽管 PM 预计会与糖反应,但目前可用的数据有限。在这项研究中,从含有 PM 和木糖的模型反应溶液中分离出一种新型亲水性化合物,并将其鉴定为(6aR,9aR)-1,8,9-三羟基-2,6a-二甲基-6a,9a-二氢环戊[5,6]吡喃[3,4-c]吡啶-7(5H)-酮,具有三环结构。该化合物似乎是通过 1-脱氧戊糖酮特异性地从戊糖形成的,其形成在 pH 值为 7.0-8.0 的范围内得到促进。在含有 30mM PM 和戊糖的反应混合物中于 90°C 加热 5 小时后,在 pH 7.4 下可得到 6.95-8.53mM 的该化合物。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/0f82/7000833/96203706e073/41598_2020_58727_Fig1_HTML.jpg

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