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缺钠大鼠对与盐酸混合的氯化钠味道的反应。

Response to NaCl taste in mixture with HCl by sodium deficient rats.

作者信息

McCutcheon B

出版信息

Physiol Behav. 1985 Jan;34(1):97-101. doi: 10.1016/0031-9384(85)90084-8.

Abstract

Sodium deficient, adrenalectomized rats and nondeficient control rats were offered, for 20 min, a mixture of 0.1 M NaCl and 0.02 N HCl. The sodium deficient rats drank substantial amounts whereas control animals were essentially indifferent to the mixture. Further tests on the sodium deficient rats with a stronger NaCl concentration in the mixture did not alter the amount drunk, which was about 1/3 the amount ingested of singly presented 0.1 NaCl. These results suggest that the sodium deficient rat can recognize the similarity of the mixture to NaCl but that the other mixture component influences the behavioral outcome in a way other than simple intensity suppression.

摘要

给缺钠的肾上腺切除大鼠和不缺钠的对照大鼠提供0.1 M氯化钠和0.02 N盐酸的混合物,持续20分钟。缺钠大鼠大量饮水,而对照动物对该混合物基本无动于衷。用混合物中氯化钠浓度更高的溶液对缺钠大鼠进行进一步测试,并未改变其饮水量,其饮水量约为单独提供0.1 M氯化钠时摄入量的1/3。这些结果表明,缺钠大鼠能够识别混合物与氯化钠的相似性,但混合物的其他成分以不同于简单强度抑制的方式影响行为结果。

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