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用腺嘌呤核苷酸类似物5'-对氟磺酰苯甲酰腺苷对大肠杆菌琥珀酰辅酶A合成酶进行化学修饰。

Chemical modification of Escherichia coli succinyl-CoA synthetase with the adenine nucleotide analogue 5'-p-fluorosulphonylbenzoyladenosine.

作者信息

Prasad A R, Ybarra J, Nishimura J S

出版信息

Biochem J. 1983 Dec 1;215(3):513-8. doi: 10.1042/bj2150513.

Abstract

Escherichia coli succinyl-CoA synthetase (EC 6.2.1.5) was irreversibly inactivated on incubation with the adenine nucleotide analogue 5'-p-fluorosulphonylbenzoyladenosine (5'-FSBA). Optimal inactivation by 5'-FSBA took place in 40% (v/v) dimethylformamide. ATP and ADP protected the enzyme against inactivation by 5'-FSBA, whereas desulpho-CoA, an analogue of CoA, did not. Inactivation of succinyl-CoA synthetase by 5'-FSBA resulted in total loss of almost four thiol groups per alpha beta-dimer, of which two groups appeared to be essential for catalytic activity. 5'-FSBA at the first instance appeared to interact non-specifically with non-essential thiol groups, followed by a more specific reaction with essential thiol groups in the ATP(ADP)-binding region. Plots of the data according to the method of Tsou [(1962) Sci. Sin. 11, 1535-1558] revealed that, of the two slower-reacting thiol groups, only one was essential for catalytic activity. When succinyl-CoA synthetase that had been totally inactivated by 5'-FSBA was unfolded in acidic urea and then refolded in the presence of 100 mM-dithiothreitol, 85% of the activity, in comparison with the appropriate control, was restored. These data are interpreted to indicate that inactivation of succinyl-CoA synthetase by 5'-FSBA involves the formation of a disulphide bond between two cysteine residues. Disulphide bond formation likely proceeds via a thiosulphonate intermediate between 5'-p-sulphonylbenzoyladenosine and one of the reactive thiol groups of the enzyme.

摘要

大肠杆菌琥珀酰辅酶A合成酶(EC 6.2.1.5)与腺嘌呤核苷酸类似物5'-对氟磺酰苯甲酰腺苷(5'-FSBA)一起孵育时会发生不可逆失活。5'-FSBA在40%(v/v)二甲基甲酰胺中能实现最佳失活效果。ATP和ADP可保护该酶不被5'-FSBA失活,而辅酶A的类似物脱硫辅酶A则不能。5'-FSBA使琥珀酰辅酶A合成酶失活导致每个αβ二聚体总共损失近四个硫醇基团,其中两个基团似乎对催化活性至关重要。5'-FSBA首先似乎与非必需硫醇基团发生非特异性相互作用,随后与ATP(ADP)结合区域中的必需硫醇基团发生更特异性的反应。根据邹氏方法[(1962)《中国科学》11, 1535 - 1558]绘制的数据图显示,在两个反应较慢的硫醇基团中,只有一个对催化活性至关重要。当被5'-FSBA完全失活的琥珀酰辅酶A合成酶在酸性尿素中展开,然后在100 mM二硫苏糖醇存在下重新折叠时,与适当对照相比,恢复了85%的活性。这些数据被解释为表明5'-FSBA使琥珀酰辅酶A合成酶失活涉及两个半胱氨酸残基之间形成二硫键。二硫键的形成可能通过5'-对磺酰苯甲酰腺苷与该酶的一个反应性硫醇基团之间的硫代磺酸酯中间体进行。

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