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[通过氨基酸残基的疏水性对细菌视紫红质和动物视紫红质结构组织的可能测定]

[Possible determination of the structural organization of bacterial and animal rhodopsins by the hydrophobicity of amino acid residues].

作者信息

Tarakhovskiĭ Iu S

出版信息

Biofizika. 1984 May-Jun;29(3):383-8.

PMID:6466718
Abstract

From a comparative analysis of the distribution of hydrophobicity in bacterial and animal (bovine) rhodopsins, the following peculiarities in the structure of these proteins have been assumed: 1) each of these proteins has 5 hydrophobic regions of equal length (20-28 residues) able to be arranged across the membrane and one region of doubled length. 2) The alpha-helix of the doubled-length regions (residues N 178-225 for bacterial rhodopsin and N 75-132 for the animal one) is characterized by pronounced amphipaticity and is capable of a retinal dependent movement in the membrane. The model of animal rhodopsin was suggested to have 13 phenylalanine residues forming a chain which "connects" 6 transmembrane segments and runs from one surface of the membrane to the opposite one.

摘要

通过对细菌视紫红质和动物(牛)视紫红质疏水性分布的比较分析,推测出这些蛋白质结构的以下特点:1)每种蛋白质都有5个长度相等(20 - 28个残基)的疏水区,能够横跨膜排列,还有一个长度加倍的区域。2)长度加倍区域的α-螺旋(细菌视紫红质的残基N 178 - 225和动物视紫红质的N 75 - 132)具有明显的两亲性,并且能够在膜中进行依赖于视黄醛的移动。动物视紫红质的模型被认为有13个苯丙氨酸残基形成一条链,该链“连接”6个跨膜片段,并从膜的一个表面延伸到相对的表面。

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