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[两种用于估计含零值的比值比的方法]

[2 solutions for estimating odds ratios with zeros].

作者信息

Valenzuela C

机构信息

Departamento de Biología Celular y Genética, Facultad de Medicina, Universidad de Chile, Santiago.

出版信息

Rev Med Chil. 1993 Dec;121(12):1441-4.

PMID:8085071
Abstract

Two solutions are proposed for the estimation of odds ratios (OR) when one or the two elements of the principal (A, D) or secondary (B, C) diagonals of a 2 x 2 matrix (A, B, C, D) are 0. The OR estimate is AD/BC. If A or D are 0, OR = 0; if B or C are 0, the OR is undefined. Analytical solution. This solution conserves the marginal totals. If B = 0 and C = 0, the OR cannot be less than AD/1 (the minimal acceptable value), then the equation (A-X) (D-X)/X2 = KAD/1 searches for that X which subtracted to A and B and added to B (0) and C (0) yields an OR K times AD; if B = 0 and C > 0 then (A-X) (D-X)/X (C+X) = AD/C; if B > 0 and C = 0, then B replaces C in the latter equation. If A and D are 0, X2/(B-X) (C-X) = 1/KBC; if A = 0 and D > 0, X (D+X)/(B-X) (C-X) = D/KBC; if A > 0 and D = 0, A replaces D in the latter equation. K can be taken at the maximum Chi squared value. Probabilistic solution. Zeros are replaced by ones and the elements of the diagonal without zeros are increased proportionally until the exact probability (Fisher) of this new matrix is equal or the nearest less than the exact probability of the original matrix. Since small numbers increase the estimation bias, the Haldane's correction should be always applied. This correction adds 0.5 to A, B C and D to estimate the OR (In OR) and adds 1 to these elements to estimate their variance.

摘要

当2×2矩阵(A、B、C、D)主对角线(A、D)或副对角线(B、C)中的一个或两个元素为0时,提出了两种估计比值比(OR)的方法。OR估计值为AD/BC。如果A或D为0,则OR = 0;如果B或C为0,则OR无定义。解析解。该解保留了边际总数。如果B = 0且C = 0,则OR不能小于AD/1(最小可接受值),那么方程(A - X)(D - X)/X² = KAD/1寻找这样一个X,从A和D中减去X并加到B(0)和C(0)上会得到一个K倍于AD的OR;如果B = 0且C > 0,则(A - X)(D - X)/X(C + X) = AD/C;如果B > 0且C = 0,则在后一个方程中B代替C。如果A和D为0,则X²/(B - X)(C - X) = 1/KBC;如果A = 0且D > 0,则X(D + X)/(B - X)(C - X) = D/KBC;如果A > 0且D = 0,则在后一个方程中A代替D。K可取最大卡方值。概率解。将0替换为1,且无0的对角线上的元素按比例增加,直到这个新矩阵的精确概率(费舍尔概率)等于或最接近小于原始矩阵的精确概率。由于小数字会增加估计偏差,所以应始终应用霍尔丹校正。此校正给A、B、C和D各加0.5来估计OR(lnOR),给这些元素各加1来估计它们的方差。

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