Chatterjee R, Bandyopadhyay U, Mazumdar A, Banerjee R K
Department of Physiology, Indian Institute of Chemical Biology, Calcutta, India.
Biochem Pharmacol. 1996 Oct 25;52(8):1169-75. doi: 10.1016/0006-2952(96)00453-4.
Lactoperoxidase (LPO, EC 1.11.1.7; donor-H2O2 oxidoreductase) catalyses the oxidation of indomethacin, a nonsteroidal antiinflammatory drug by H2O2 as measured by time-dependent decay of indo-methacin extinction at 280 nm and concurrent appearance of stable oxidation product(s) at 412 nm. From a plot of log Vmax against varying pH of indomethacin oxidation, involvement of an ionizable group of the enzyme having pka = 5.7 could be ascertained for controlling the oxidation process. Spectral studies revealed that LPO-compound II oxidises indomethacin through one-electron transfer and is reduced to the native ferric state as shown by its spectral shift from 430 nm to 412 nm through an isosbestic point at 421 nm. The one-electron oxidation product is a nitrogen-centered free radical detected as a 5,5-dimethyl-l-pyrroline N-oxide (DMPO) adduct (alpha N = 15 G, alpha H beta = 16 G) in electron spin resonance spectroscopy. The free radical is scavenged by reaction with O2 as shown by O2 consumption sensitive to the free-radical trap, DMPO. Binding studies by optical difference spectroscopy indicate that indomethacin binds to LPO with an apparent KD value of 24.5 microM. The free energy change, delta G', for the binding is -26.3 KJ mol-1, suggesting that the interaction is favourable for oxidation. Indomethacin binding remains unaltered by a change of pH from 5.25 to 7.5, presumably because of hydrophobic interaction. The binding is competitive with resorcinol, an aromatic electron donor, showing the KD value to be as high as 100 microM. We suggest that indomethacin interacts at the aromatic donor binding site and is oxidised by one-electron transfer by LPO catalytic intermediates to stable oxidation product(s) through the formation of a free radical.
乳过氧化物酶(LPO,EC 1.11.1.7;供体 - H2O2氧化还原酶)催化非甾体抗炎药吲哚美辛被H2O2氧化,这可通过280 nm处吲哚美辛吸光度随时间的衰减以及412 nm处稳定氧化产物的同时出现来测定。从吲哚美辛氧化的log Vmax对不同pH值的作图中,可以确定pKa = 5.7的酶的可电离基团参与了氧化过程的控制。光谱研究表明,LPO - 化合物II通过单电子转移氧化吲哚美辛,并还原为天然铁状态,这通过其光谱从430 nm通过421 nm的等吸收点移至412 nm得以证明。单电子氧化产物是一种以氮为中心的自由基,在电子自旋共振光谱中被检测为5,5 - 二甲基 - 1 - 吡咯啉N - 氧化物(DMPO)加合物(αN = 15 G,αHβ = 16 G)。自由基通过与O2反应被清除,这通过对自由基捕获剂DMPO敏感的O2消耗得以证明。通过光学差示光谱进行的结合研究表明,吲哚美辛与LPO结合,表观KD值为24.5 μM。结合的自由能变化ΔG'为 - 26.3 KJ mol-1,表明这种相互作用有利于氧化。从pH 5.25到7.5的变化不会改变吲哚美辛的结合,大概是由于疏水相互作用。这种结合与间苯二酚(一种芳香族电子供体)具有竞争性,KD值高达100 μM。我们认为吲哚美辛在芳香族供体结合位点相互作用,并通过LPO催化中间体的单电子转移被氧化为稳定的氧化产物,过程中形成自由基。