Sekizawa S I, French A S, Torkkeli P H
Department of Physiology and Biophysics, Dalhousie University, Halifax, Nova Scotia B3H 4H7, Canada.
J Neurophysiol. 2000 Feb;83(2):746-53. doi: 10.1152/jn.2000.83.2.746.
Low-voltage-activated Ca(2+) currents (LVA-I(Ca)) are believed to perform several roles in neurons such as lowering the threshold for action potentials, promoting burst firing and oscillatory behavior, and enhancing synaptic excitation. They also may allow rapid increases in intracellular Ca(2+) concentration. We discovered LVA-I(Ca) in both members of paired mechanoreceptor neurons in a spider, where one neuron adapts rapidly (Type A) and the other slowly (Type B) in response to a step stimulus. To learn if I(Ca) contributed to the difference in adaptation behavior, we studied the kinetics of I(Ca) from isolated somata under single-electrode voltage-clamp and tested its physiological function under current clamp. LVA-I(Ca) was large enough to fire single action potentials when all other voltage-activated currents were blocked, but we found no evidence that it regulated firing behavior. LVA-I(Ca) did not lower the action potential threshold or affect firing frequency. Previous experiments have failed to find Ca(2+)-activated K(+) current (I(K(Ca))) in the somata of these neurons, so it is also unlikely that LVA-I(Ca) interacts with I(K(Ca)) to produce oscillatory behavior. We conclude that LVA-Ca(2+) channels in the somata, and possible in the dendrites, of these neurons open in response to the depolarization caused by receptor current and by the voltage-activated Na(+) current (I(Na)) that produces action potential(s). However, the role of the increased intracellular Ca(2+) concentration in neuronal function remains enigmatic.
低电压激活的Ca(2+)电流(LVA-I(Ca))被认为在神经元中发挥多种作用,如降低动作电位阈值、促进爆发式放电和振荡行为以及增强突触兴奋。它们还可能使细胞内Ca(2+)浓度迅速升高。我们在蜘蛛的成对机械感受器神经元中均发现了LVA-I(Ca),其中一个神经元对阶跃刺激快速适应(A型),另一个则缓慢适应(B型)。为了解I(Ca)是否导致了适应行为的差异,我们在单电极电压钳制下研究了分离胞体中I(Ca)的动力学,并在电流钳制下测试了其生理功能。当所有其他电压激活电流被阻断时,LVA-I(Ca)大到足以引发单个动作电位,但我们没有发现它调节放电行为的证据。LVA-I(Ca)没有降低动作电位阈值或影响放电频率。先前的实验未能在这些神经元的胞体中发现Ca(2+)激活的K(+)电流(I(K(Ca))),因此LVA-I(Ca)也不太可能与I(K(Ca))相互作用以产生振荡行为。我们得出结论,这些神经元胞体以及可能的树突中的LVA-Ca(2+)通道会响应受体电流和产生动作电位的电压激活Na(+)电流(I(Na))引起的去极化而开放。然而,细胞内Ca(2+)浓度升高在神经元功能中的作用仍然是个谜。