Suppr超能文献

5-氮杂胞苷和 Hoechst 诱导印度麂产生非整倍体。

5-Azacytidine- and Hoechst-induced aneuploidy in Indian muntjac.

作者信息

Vig B K, Hallett W H

机构信息

Department of Biology/314, University of Nevada, Reno, NV 89557-0015, USA.

出版信息

Mutat Res. 2000 Mar 3;466(1):79-86. doi: 10.1016/s1383-5718(00)00006-1.

Abstract

Hoechst 33258 (bis-benzimidazole) and 5-azacytidine (5-AC) cause decondensation of the pericentric heterochromatin in mouse and aberrations in the sequence of centromere separation apparently by different mechanisms. We treated the male Indian muntjac cells (2n=7), which do not undergo decondensation of the pericentric heterochromatin, to study if these chemicals would result in induction of aneuploidy limited to the Y(2) chromosome. This paper reports that both agents result in aneuploidy primarily limited to one chromosome, the Y(2). It is likely that other chromosomes are not tolerated in aneuploid condition because every chromosome carries some household genes including those essential for mitotic progression. The loss/gain of the Y(2) chromosome is tolerated because it is the smallest chromosome and is almost entirely composed of constitutive heterochromatin. Since Indian muntjac has only three pairs of large chromosomes comprising its basic genome, which can be clearly viewed under high dry objective, these cells are very suitable for the preliminary analysis of aneuploidy-inducing ability of various chemicals.

摘要

Hoechst 33258(双苯并咪唑)和5-氮杂胞苷(5-AC)会导致小鼠着丝粒周围异染色质解聚,并明显通过不同机制引起着丝粒分离序列异常。我们用雄性印度麂细胞(2n = 7)进行处理,该细胞不会发生着丝粒周围异染色质解聚,以研究这些化学物质是否会导致仅限于Y(2)染色体的非整倍体诱导。本文报道这两种试剂都会导致非整倍体,主要限于一条染色体,即Y(2)。其他染色体在非整倍体状态下可能无法耐受,因为每条染色体都携带一些看家基因,包括那些对有丝分裂进程至关重要的基因。Y(2)染色体的丢失/增加是可以耐受的,因为它是最小的染色体,几乎完全由组成型异染色质组成。由于印度麂只有三对构成其基本基因组的大染色体,在高倍干燥物镜下可以清楚地看到,这些细胞非常适合对各种化学物质的非整倍体诱导能力进行初步分析。

文献AI研究员

20分钟写一篇综述,助力文献阅读效率提升50倍。

立即体验

用中文搜PubMed

大模型驱动的PubMed中文搜索引擎

马上搜索

文档翻译

学术文献翻译模型,支持多种主流文档格式。

立即体验