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超氧阴离子自由基还原细胞色素c的动力学。

The kinetics of the reduction of cytochrome c by the superoxide anion radical.

作者信息

Koppenol W H, van Buuren K J, Butler J, Braams R

出版信息

Biochim Biophys Acta. 1976 Nov 9;449(2):157-68. doi: 10.1016/0005-2728(76)90130-4.

Abstract
  1. At neutral pH ferricytochrome c is reduced by the superoxide anion radical (O2-), without loss of enzymatic activity, by a second order process in which no intermediates are observed. The yield of ferrocytochrome c (82-104%), as related to the amount of O2- produced, is slightly dependent on the concentration of sodium formate in the matrix solution. 2. The reaction (k1 equals (1.1+/-0.1) - 10(6) M-1 - s-1 at pH 7.2, I equals 4 mM and 21 degrees C) can be inhibited by superoxide dismutase and trace amounts of copper ions. The inhibition by copper ions is removed by EDTA without interference in the O2- reduction reaction. 3. The second-order rate constant for the reaction of O2- with ferricytochrome c depends on the pH of the matrix solution, decreasing rapidly at pH greater than 8. The dependence of the rate constant on the pH can be explained by assuming that only the neutral form of ferricytochrome c reacts with O2- and that the alkaline form of the hemoprotein is unreactive. From studies at pH 8.9, the rate for the transition from the alkaline to the neutral form of ferricytochrome c can be estimated to be 0.3 s-1 (at 21 degrees C and I equals 4 mM). 4. The second-order rate constant for the reaction of O2- with ferricytochrome c is also dependent on the ionic strength of the medium. From a plot of log k1 versus I1/2-(I + alphaI1/2)-1 we determined the effective charge on the ferricytochrome c molecule as +6.3 and the rate constant at I equals 0 as (3.1+/-0.1) - 10(6) M-1 - s-1 (pH 7.1, 21 degrees C). 5. The possibility that singlet oxygen is formed as a product of the reaction of O2- with ferricytochrome c can be ruled out on thermodynamic grounds.
摘要
  1. 在中性pH条件下,高铁细胞色素c可被超氧阴离子自由基(O₂⁻)还原,且酶活性不会丧失,这是一个二级反应过程,在此过程中未观察到中间体。与产生的O₂⁻量相关的亚铁细胞色素c的产率(82 - 104%)在一定程度上依赖于基质溶液中甲酸钠的浓度。2. 该反应(在pH 7.2、离子强度I = 4 mM及21℃时,k₁ = (1.1 ± 0.1) × 10⁶ M⁻¹·s⁻¹)可被超氧化物歧化酶和痕量铜离子抑制。铜离子的抑制作用可被乙二胺四乙酸(EDTA)消除,且不会干扰O₂⁻的还原反应。3. O₂⁻与高铁细胞色素c反应的二级速率常数取决于基质溶液的pH,在pH大于8时迅速降低。速率常数对pH的依赖性可以通过假设只有中性形式的高铁细胞色素c与O₂⁻反应,而血红蛋白的碱性形式无反应来解释。从pH 8.9的研究中可以估计,高铁细胞色素c从碱性形式转变为中性形式的速率为0.3 s⁻¹(在21℃和I = 4 mM时)。4. O₂⁻与高铁细胞色素c反应的二级速率常数也依赖于介质的离子强度。通过绘制log k₁对I¹/₂ - (I + αI¹/₂)⁻¹的曲线,我们确定高铁细胞色素c分子上的有效电荷为 +6.3,且在I = 0时的速率常数为(3.1 ± 0.1) × 10⁶ M⁻¹·s⁻¹(pH 7.1,21℃)。5. 基于热力学原理,可以排除单线态氧作为O₂⁻与高铁细胞色素c反应产物形成的可能性。

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