Haile S M, Wuensch B J
Materials Science, California Institute of Technology, Pasadena, CA 91125, USA.
Acta Crystallogr B. 2000 Oct;56 ( Pt 5):773-9. doi: 10.1107/S0108768100006704. Epub 2000 Oct 1.
Hydrothermal investigations in the high-silica region of the K(2)O-Nd(2)O(3)-SiO(2) system, carried out in a search for novel fast-ion conductors (FICs), yielded the new compound tripotassium neodymium heptasilicate, K(3)NdSi(7)O(17). Single-crystal X-ray methods revealed that K(3)NdSi(7)O(17) crystallizes in space group P3, has lattice constants a = 16.131 (2) and c = 7.7146 (19) A, Z = 4, and 22 atoms in the asymmetric unit. Refinement was carried out to a residual, R(F), of 0.0253 and a weighted residual, wR(F(2)), of 0.0702 using anisotropic displacement parameters for all atoms. The silicate anion forms an interrupted framework, within which both Nd octahedra and K polyhedra are situated. The structure is unusual in that it contains a symmetry-constrained Si-O-Si bond angle of 180 degrees. No isomorphs to K(3)NdSi(7)O(17) are known.
在K₂O-Nd₂O₃-SiO₂体系的高硅区域进行的水热研究,旨在寻找新型快离子导体(FICs),得到了新化合物七硅酸钾钕K₃NdSi₇O₁₇。单晶X射线方法表明,K₃NdSi₇O₁₇属于P3空间群,晶格常数a = 16.131 (2) Å,c = 7.7146 (19) Å,Z = 4,不对称单元中有22个原子。使用所有原子的各向异性位移参数进行精修,最终残余因子R(F)为0.0253,加权残余因子wR(F²)为0.0702。硅酸根阴离子形成一个间断的骨架,Nd八面体和K多面体都位于其中。该结构不同寻常之处在于它包含一个受对称性约束的180° Si-O-Si键角。目前还不知道有与K₃NdSi₇O₁₇同构的物质。