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如何测量黄嘌呤氧化酶产生的超氧化物产量?

How should xanthine oxidase-generated superoxide yields be measured?

作者信息

Hodges G R, Young M J, Paul T, Ingold K U

机构信息

Steacie Institute for Molecular Sciences, National Research Council of Canada, Ottawa, Ontario, Canada.

出版信息

Free Radic Biol Med. 2000 Sep 1;29(5):434-41. doi: 10.1016/s0891-5849(00)00298-7.

Abstract

The rate of formation of superoxide measured by its reduction of tetranitromethane (TNM) and by its reduction of ferric cytochrome c (Fe(III) cc) are in excellent agreement when the superoxide is generated from a simple chemical precursor. In contrast, the rate of formation of superoxide generated in the reaction of xanthine oxidase with acetaldehyde is much higher (up to a factor of 6) when measured with TNM and compared with Fe(III) cc. It is shown that Fe(III) cc measures superoxide that has diffused from the enzyme, and that TNM probably scavenges all the dioxygen that is reduced by one electron by the enzyme. The TNM traps enzyme-bound superoxide in competition with the second-electron transfer and proton transfer, which normally yield hydrogen peroxide. The proton transfer is probably rate determining, k(p) </= 3.8x10(3)s(-1).

摘要

当超氧化物由简单化学前体产生时,通过其对四硝基甲烷(TNM)的还原以及对细胞色素c铁(III)(Fe(III) cc)的还原所测得的超氧化物生成速率高度一致。相比之下,用TNM测量并与Fe(III) cc比较时,黄嘌呤氧化酶与乙醛反应中生成的超氧化物生成速率要高得多(高达6倍)。结果表明,Fe(III) cc测量的是从酶中扩散出来的超氧化物,而TNM可能清除了酶通过单电子还原的所有二氧。TNM在与通常产生过氧化氢的第二次电子转移和质子转移的竞争中捕获酶结合的超氧化物。质子转移可能是速率决定因素,k(p) ≤ 3.8x10(3)s(-1)。

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