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人类基因组中有多少有害突变?

How many deleterious mutations are there in the human genome?

作者信息

Morris J A

机构信息

Consultant Pathologist, Royal Lancaster Infirmary, Lancaster, UK.

出版信息

Med Hypotheses. 2001 May;56(5):646-52. doi: 10.1054/mehy.2000.1200.

Abstract

An estimate of the number of deleterious mutations in the human genome is made using data on the frequency of rare recessive disease in cousin marriages and in the general population. Sexual reproduction ensures that deleterious mutations are distributed at random in zygotes with an approximate Poisson distribution. The mean of this distribution is the sum of the mean number of deleterious mutations in zygotes which contribute to the next generation (Y) and the mean number of new mutations which arise in each human generation (X). The estimates are that X is between 1 and 2.6 and Y is between 12 and 32. A mathematical model based on redundancy is then used to predict how zygote survival will vary with the number of deleterious mutations. The form of this relationship is the same as that seen in experiments on cell survival following radiation-induced mutational damage and this provides independent support for this theoretical approach. The zygotes that survive to contribute to the next generation have a skewed distribution with a mean of Y. It is argued that the number of deleterious mutations in the genome is an important variable in health and disease.

摘要

利用表亲婚姻和普通人群中罕见隐性疾病的频率数据,对人类基因组中有害突变的数量进行了估计。有性生殖确保有害突变以近似泊松分布随机分布在受精卵中。该分布的均值是对下一代有贡献的受精卵中有害突变的平均数量(Y)与每代人类中出现的新突变的平均数量(X)之和。估计X在1到2.6之间,Y在12到32之间。然后使用基于冗余的数学模型来预测受精卵存活率将如何随有害突变的数量而变化。这种关系的形式与辐射诱导突变损伤后细胞存活实验中观察到的相同,这为这种理论方法提供了独立支持。存活下来并对下一代有贡献的受精卵具有均值为Y的偏态分布。有人认为,基因组中有害突变的数量是健康和疾病中的一个重要变量。

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