Fan Y, Sirotkin A, Russell R G, Ayala J, Skoultchi A I
Department of Cell Biology, Albert Einstein College of Medicine, Bronx, New York 10461, USA.
Mol Cell Biol. 2001 Dec;21(23):7933-43. doi: 10.1128/MCB.21.23.7933-7943.2001.
H1 linker histones are involved in facilitating the folding of chromatin into a 30-nm fiber. Mice contain eight H1 subtypes that differ in amino acid sequence and expression during development. Previous work showed that mice lacking H1(0), the most divergent subtype, develop normally. Examination of chromatin in H1(0-/-) mice showed that other H1s, especially H1c, H1d, and H1e, compensate for the loss of H1(0) to maintain a normal H1-to-nucleosome stoichiometry, even in tissues that normally contain abundant amounts of H1(0) (A. M. Sirotkin et al., Proc. Natl. Acad. Sci. USA 92:6434-6438, 1995). To further investigate the in vivo role of individual mammalian H1s in development, we generated mice lacking H1c, H1d, or H1e by homologous recombination in mouse embryonic stem cells. Mice lacking any one of these H1 subtypes grew and reproduced normally and did not exhibit any obvious phenotype. To determine whether one of these H1s, in particular, was responsible for the compensation present in H1(0-/-) mice, each of the three H1 knockout mouse lines was bred with H1(0) knockout mice to generate H1c/H1(0), H1d/H1(0), or H1e/H1(0) double-knockout mice. Each of these doubly H1-deficient mice also was fertile and exhibited no anatomic or histological abnormalities. Chromatin from the three double-knockout strains showed no significant change in the ratio of total H1 to nucleosomes. These results suggest that any individual H1 subtype is dispensable for mouse development and that loss of even two subtypes is tolerated if a normal H1-to-nucleosome stoichiometry is maintained. Multiple compound H1 knockouts will probably be needed to disrupt the compensation within this multigene family.
H1连接组蛋白参与促进染色质折叠成30纳米纤维。小鼠含有八种H1亚型,它们在发育过程中的氨基酸序列和表达存在差异。先前的研究表明,缺乏最具差异的亚型H1(0)的小鼠发育正常。对H1(0-/-)小鼠的染色质检查表明,其他H1,尤其是H1c、H1d和H1e,可补偿H1(0)的缺失,以维持正常的H1与核小体化学计量比,即使在通常含有大量H1(0)的组织中也是如此(A.M.西罗特金等人,《美国国家科学院院刊》92:6434-6438,1995)。为了进一步研究单个哺乳动物H1在发育中的体内作用,我们通过小鼠胚胎干细胞中的同源重组产生了缺乏H1c、H1d或H1e的小鼠。缺乏这些H1亚型中任何一种的小鼠生长和繁殖正常,没有表现出任何明显的表型。为了确定这些H1中是否有一个特别负责H1(0-/-)小鼠中的补偿作用,将三个H1基因敲除小鼠品系分别与H1(0)基因敲除小鼠杂交,以产生H1c/H1(0)、H1d/H1(0)或H1e/H1(0)双基因敲除小鼠。这些H1双缺失小鼠每只也都能生育,没有表现出解剖学或组织学异常。来自这三个双基因敲除品系的染色质显示,总H1与核小体的比例没有显著变化。这些结果表明,任何单个H1亚型对小鼠发育都是可有可无的,并且如果维持正常的H1与核小体化学计量比,即使缺失两种亚型也能被耐受。可能需要多个复合H1基因敲除来破坏这个多基因家族中的补偿作用。