Gelli Angie
Department of Internal Medicine, Division of Infectious and Immunologic Diseases, University of California, Davis, 1 Shields Avenue, School of Medicine, Tupper Hall, Room 3326, Davis, CA 95616, USA.
Mol Microbiol. 2002 Nov;46(3):845-54. doi: 10.1046/j.1365-2958.2002.03213.x.
In the budding yeast Saccharomyces cerevisiae, the preservation of the mating competent haploid (a or alpha) and the mating incompetent diploid (a/alpha) is necessary to prevent aneuploidy. Once haploid cells respond to pheromone, the mating-specific signal transduction pathway is activated, and the MAP kinase Fus3 phosphorylates two specific repressor proteins Rst1 and Rst2 (also known as Dig1 and Dig2) to promote Ste12-dependent transcription of mating-specific genes. In contrast, diploid cells cannot mate because genes that encode components of the mating pathway are repressed through the combined action of the Mata1-Matalpha2 and Matalpha2-Mcm1 repressors. Surprisingly, repression of Ste12 by Rst1 and Rst2 is essential for diploid sterility. Homozygous deletion of both RST1 and RST2 (rst-) causes a/alpha diploid cells constitutively to express a-specific genes and mate preferentially as a-cells. This phenotype is sensitive to Ste12 dosage, as removal of one copy of STE12 completely reduces the ectopic activation of a-specific genes. The Matalpha2-Mcm1 complex, which normally represses a-specific genes, is defective in rst- diploids because Matalpha2 is destabilized in rst- diploids, possibly as a consequence of its relocalization from the nucleus to the cytoplasm. This study finds that Rst1 and Rst2 are necessary for the a/alpha diploid cell type. Rst1 and Rst2 are required in order to prevent the amplification of a robust Ste12 transcriptional programme that appears to over-ride Matalpha2-dependent repression of haploid and a-specific genes.
在出芽酵母酿酒酵母中,保持具有交配能力的单倍体(a或α)和无交配能力的二倍体(a/α)对于防止非整倍体形成至关重要。一旦单倍体细胞对信息素作出反应,交配特异性信号转导途径就会被激活,丝裂原活化蛋白激酶Fus3会磷酸化两种特异性阻遏蛋白Rst1和Rst2(也称为Dig1和Dig2),以促进依赖Ste12的交配特异性基因转录。相比之下,二倍体细胞不能交配,因为编码交配途径成分的基因通过Mata1-Matalpha2和Matalpha2-Mcm1阻遏物的联合作用被抑制。令人惊讶的是,Rst1和Rst2对Ste12的抑制对于二倍体不育至关重要。RST1和RST2的纯合缺失(rst-)导致a/α二倍体细胞组成型表达a特异性基因,并优先作为a细胞进行交配。这种表型对Ste12剂量敏感,因为去除一份STE12拷贝会完全降低a特异性基因的异位激活。通常抑制a特异性基因的Matalpha2-Mcm1复合物在rst-二倍体中存在缺陷,因为Matalpha2在rst-二倍体中不稳定,这可能是其从细胞核重新定位到细胞质的结果。本研究发现Rst1和Rst2对于a/α二倍体细胞类型是必需的。为了防止强大的Ste12转录程序的扩增,Rst1和Rst2是必需的,该转录程序似乎会超越Matalpha2对单倍体和a特异性基因的依赖性抑制。