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基于丙氨酸的短肽在水溶液中可能形成3(10)螺旋而非α螺旋。

Short alanine-based peptides may form 3(10)-helices and not alpha-helices in aqueous solution.

作者信息

Miick S M, Martinez G V, Fiori W R, Todd A P, Millhauser G L

机构信息

Department of Chemistry and Biochemistry, University of California, Santa Cruz 95064.

出版信息

Nature. 1992 Oct 15;359(6396):653-5. doi: 10.1038/359653a0.

DOI:10.1038/359653a0
PMID:1328890
Abstract

Short alanine peptides, containing 16 or 17 residues, appear to form alpha-helices in aqueous solution. But the main spectroscopic analyses used on helical peptides (circular dichroism and nuclear magnetic resonance) cannot distinguish between an alpha-helix (in which the ith residue is hydrogen-bonded to residue i + 4; ref. 9) and the next most common peptide helix, the 3(10)-helix10 (i-->i + 3 hydrogen-bonding). To address this problem we have designed single and doubly spin-labelled analogues of alanine-based peptides in which the nitroxide spin label forms an unbranched side chain extending from the sulphur atom of a cysteine residue. Here we report the circular dichroism, Fourier-transform infrared and electron-spin resonance spectra of these peptides under helix-forming conditions. The infrared absorbance gives an amide I' band with a frequency that is substantially different from that observed for alpha-helices. The electron-spin resonance spectra of doubly labelled helices show that the ranking of distances between side chains, around a single turn (residues 4-8), is inconsistent with an alpha-helical structure. Our experiments suggest that the more likely peptide geometry is a 3(10)-helix.

摘要

含有16或17个残基的短丙氨酸肽似乎在水溶液中形成α螺旋。但是用于螺旋肽的主要光谱分析方法(圆二色性和核磁共振)无法区分α螺旋(其中第i个残基与第i + 4个残基形成氢键;参考文献9)和下一个最常见的肽螺旋,即3(10)-螺旋10(i→i + 3氢键结合)。为了解决这个问题,我们设计了基于丙氨酸的肽的单自旋标记和双自旋标记类似物,其中氮氧自旋标记形成从半胱氨酸残基的硫原子延伸的无分支侧链。在此我们报告了这些肽在螺旋形成条件下的圆二色性、傅里叶变换红外光谱和电子自旋共振光谱。红外吸收给出了一个酰胺I'带,其频率与α螺旋所观察到的频率有很大不同。双标记螺旋的电子自旋共振光谱表明,在单一圈(残基4 - 8)周围侧链之间距离的排序与α螺旋结构不一致。我们的实验表明,更可能的肽几何结构是3(10)-螺旋。

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