白色瘤胃球菌中的多糖储存与生长效率
POLYSACCHARIDE STORAGE AND GROWTH EFFICIENCY IN RUMINOCOCCUS ALBUS.
作者信息
HUNGATE R E
出版信息
J Bacteriol. 1963 Oct;86(4):848-54. doi: 10.1128/jb.86.4.848-854.1963.
Abstract
Hungate, R. E. (University of California, Davis). Polysaccharide storage and growth efficiency in Ruminococcus albus. J. Bacteriol. 86:848-854. 1963.-Ruminococcus albus strain RAM requires biotin, p-aminobenzoic acid, pyridoxamine, isovalerate, isobutyrate, 2-methylbutyrate, and either cysteine or sulfide. Rumen fluid and casein hydrolysate improve growth but are not essential. Up to 35% iodophilic polysaccharide is stored in cells from batch cultures and 17% in a continuous culture on a 10-hr cycle. The storage product is a polymer of glucose resembling starch. The yield of cells in continuous culture, corrected for stored starch, averaged 102 mg per mmole of cellobiose fermented to waste products. It is postulated that nine high-energy phosphates are derived from each cellobiose molecule. Conversions providing this number are discussed.
摘要
洪盖特，R.E.（加利福尼亚大学戴维斯分校）。白色瘤胃球菌中的多糖储存与生长效率。《细菌学杂志》86:848 - 854。1963年。——白色瘤胃球菌菌株RAM需要生物素、对氨基苯甲酸、吡哆胺、异戊酸、异丁酸、2 - 甲基丁酸，以及半胱氨酸或硫化物。瘤胃液和酪蛋白水解物可促进生长，但并非必需。在分批培养中，细胞内可储存高达35%的嗜碘多糖，在10小时周期的连续培养中为17%。储存产物是一种类似淀粉的葡萄糖聚合物。经校正储存淀粉后，连续培养中细胞的产量平均为每发酵至废物的毫摩尔纤维二糖产生102毫克细胞。据推测，每个纤维二糖分子可产生九个高能磷酸键。文中讨论了能提供此数量的转化过程。
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