Graves J A M
Research School of Biological Sciences, The Australian National University, Canberra, ACT, Australia.
Cytogenet Genome Res. 2003;101(3-4):278-82. doi: 10.1159/000074349.
Birds show female heterogamety, with ZZ males and ZW females. It is still not clear whether the W is female-determining, or whether two doses of the Z chromosomes are male-determining, or both. This question could easily be settled by the sexual phenotypes of ZZW and ZO birds, in the same way that the sexual phenotypes of XXY and XO showed that the Y is male determining in humans, but that the dosage of an X-borne gene determines sex in Drosophila. However, despite extensive searches, no ZZW or ZO diploid birds have been satisfactorily documented, so we must assume that these genotypes are embryonic lethals. Given that ZW and ZZ are viable and the W contains few genes it is not clear why this should be so. Here I propose that sex chromosome aneuploids are lethal in chicken because, to achieve dosage compensation, a locus on the W chromosome controls the upregulation of genes on the Z in ZW females. ZO birds would therefore have only half the normal dose of Z-linked gene product and ZZW would have twice the amount, both of which would undoubtedly be incompatible with life. Reports of other aneuploids and triploids are also consistent with this hypothesis.
鸟类表现出雌性异配性别,雄性为ZZ,雌性为ZW。目前尚不清楚W染色体是否决定雌性,或者两份Z染色体剂量是否决定雄性,还是两者都起决定作用。这个问题可以通过ZZW和ZO鸟类的性表型轻松解决,就像XXY和XO的性表型表明人类中Y染色体决定雄性,但果蝇中X染色体上基因的剂量决定性别一样。然而,尽管进行了广泛的搜索,尚未有令人满意的文献记录ZZW或ZO二倍体鸟类,所以我们必须假定这些基因型是胚胎致死的。鉴于ZW和ZZ是存活的,且W染色体上基因很少,不清楚为何会这样。在此我提出,性染色体非整倍体在鸡中是致死的,因为为了实现剂量补偿,W染色体上的一个位点控制ZW雌性中Z染色体上基因的上调。因此,ZO鸟类的Z连锁基因产物剂量只有正常剂量的一半,而ZZW的剂量则是两倍,这两者无疑都与生命不相容。关于其他非整倍体和三倍体的报道也与这一假设一致。