Campos-Fernández Cristian Saul, Schottel Brandi L, Chifotides Helen T, Bera Jitendra K, Bacsa John, Koomen John M, Russell David H, Dunbar Kim R
Department of Chemistry, Texas A&M University, College Station, Texas 77842, USA.
J Am Chem Soc. 2005 Sep 21;127(37):12909-23. doi: 10.1021/ja052108q.
Reactions of 3,6-bis(2-pyridyl)-1,2,4,5-tetrazine (bptz) with solvated first-row transition metals M(II) (M(II) = Ni, Zn, Mn, Fe, Cu) have been explored with emphasis on the factors that influence the identity of the resulting cyclic products for Ni(II) and Zn(II). The relatively small anions, namely [ClO4]- and [BF4]-, lead to the formation of molecular squares [{M4(bptz)4(CH3CN)8} subsetX][X]7, (M = Zn(II), Ni(II); X = [BF4]-, [ClO4]-), whereas the larger anion [SbF6]- favors the molecular pentagon [{Ni5(bptz)5-(CH3CN)10} subsetSbF6][SbF6]9. The molecular pentagon easily converts to the square in the presence of excess [BF4]-, [ClO4]-, and [I]- anions, whereas the Ni(II) square can be partially converted to the less stable pentagon under more forcing conditions in the presence of excess [SbF6]- ions. No evidence for the molecular square being in equilibrium with the pentagon was observed in the ESI-MS spectra of the individual square and pentagon samples. Anion-exchange reactions of the encapsulated ion in [{Ni4(bptz)4(CH3CN)8} subsetClO4][ClO4]7 reveal that a larger anion such as [IO4]- cannot replace [ClO4]- inside the cavity, but that the linear [Br3]- anion is capable of doing so. ESI-MS studies of the reaction between [Ni(CH3CN)6][NO3]2 and bptz indicate that the product is trinuclear. Mass spectral studies of the bptz reactions with Mn(II), Fe(II), and Cu(II), in the presence of [ClO4]- anions, support the presence of molecular squares. The formation of the various metallacyclophanes is discussed in light of the factors that influence these self-assembly reactions, such as choice of metal ion, anion, and solvent.
研究了3,6-双(2-吡啶基)-1,2,4,5-四嗪(bptz)与溶剂化的第一行过渡金属M(II)(M(II)=Ni、Zn、Mn、Fe、Cu)的反应,重点关注影响Ni(II)和Zn(II)所得环状产物结构的因素。相对较小的阴离子,即[ClO4]-和[BF4]-,导致形成分子正方形[{M4(bptz)4(CH3CN)8} subsetX][X]7,(M = Zn(II),Ni(II);X = [BF4]-,[ClO4]-),而较大的阴离子[SbF6]-则有利于形成分子五边形[{Ni5(bptz)5-(CH3CN)10} subsetSbF6][SbF6]9。在过量的[BF4]-、[ClO4]-和[I]-阴离子存在下,分子五边形很容易转化为正方形,而在过量的[SbF6]-离子存在下,在更苛刻的条件下,Ni(II)正方形可以部分转化为稳定性较差的五边形。在单个正方形和五边形样品的电喷雾电离质谱(ESI-MS)中未观察到分子正方形与五边形处于平衡状态的证据。[{Ni4(bptz)4(CH3CN)8} subsetClO4][ClO4]7中包封离子的阴离子交换反应表明,较大的阴离子如[IO4]-不能取代腔内的[ClO4]-,但线性的[Br3]-阴离子能够做到这一点。[Ni(CH3CN)6][NO3]2与bptz反应的ESI-MS研究表明产物是三核的。在[ClO4]-阴离子存在下,bptz与Mn(II)、Fe(II)和Cu(II)反应的质谱研究支持了分子正方形的存在。根据影响这些自组装反应的因素,如金属离子、阴离子和溶剂的选择,讨论了各种金属环烷的形成。