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基于d0的烯烃复分解催化剂,Re([三键]CR)(=CHR)(X)(Y):X和Y配体对高效活性位点的关键作用。

d0 Re-based olefin metathesis catalysts, Re([triple bond]CR)(=CHR)(X)(Y): the key role of X and Y ligands for efficient active sites.

作者信息

Solans-Monfort Xavier, Clot Eric, Copéret Christophe, Eisenstein Odile

机构信息

LSDSMS (UMR 5636 CNRS), cc 14, Institut Gerhardt, Université Montpellier 2, F-34095 Montpellier Cedex 5, France.

出版信息

J Am Chem Soc. 2005 Oct 12;127(40):14015-25. doi: 10.1021/ja053528i.

DOI:10.1021/ja053528i
PMID:16201824
Abstract

DFT(B3PW91) calculations show that the reaction pathways for ethylene metathesis with Re([triple bond]CMe)(=CHMe)(X)(Y) (X/Y = CH2CH3/CH2CH3; CH2CH3/OSiH3; OSiH3/CH2CH3; OCH3/OCH3, CH2CH3/OCH3, and OCF3/OCF3) occur in two steps: first, the pseudo-tetrahedral d0 Re complexes distort to a trigonal pyramid to open a coordination site for ethylene, which remains far from Re (early transition state for C-C bond formation). The energy barrier, determined by the energy required to distort the catalyst, is the lowest for unsymmetrical ligands (X not equal Y) when the apical site of the TBP is occupied by a good sigma-donor ligand (X) and the basal site by a poor sigma-donor (Y). Second, the formation of metallacyclobutanes (late transition state for C-C bond formation) has a low energy barrier for any type of ligands, decreasing for poor sigma-donor X and Y ligands, because they polarize the Re-C alkylidene bond as Re(+delta)=C(-delta), which favors the reaction with ethylene, itself polarized by the metal center in the reverse way. The metallacyclobutane is also a TBP, with apical alkylidyne and Y ligands, and it is stabilized by poor sigma-donor X and Y. The best catalyst will have the more shallow potential energy surface, and will thus be obtained for the unsymmetrical set of ligands with X = a good sigma-donor (alkyl) and Y = a poor sigma-donor (O-based ligand). This rationalizes the high efficiency of well-defined Re alkylidene supported on silica, compared to its homogeneous equivalent, Re([triple bond]CMe)(=CHMe)(OR)2.

摘要

密度泛函理论(DFT,B3PW91)计算表明,乙烯与Re([三键]CMe)(=CHMe)(X)(Y)(X/Y = CH2CH3/CH2CH3;CH2CH3/OSiH3;OSiH3/CH2CH3;OCH3/OCH3、CH2CH3/OCH3和OCF3/OCF3)发生复分解反应的途径分两步进行:首先,伪四面体d0铼配合物扭曲成三角锥,为乙烯打开一个配位位点,乙烯与铼保持较远的距离(C-C键形成的早期过渡态)。由扭曲催化剂所需能量决定的能垒,对于不对称配体(X不等于Y)来说是最低的,当三角双锥的顶点位置被一个良好的σ-给体配体(X)占据,而底面位置被一个较差的σ-给体(Y)占据时。其次,金属环丁烷的形成(C-C键形成的晚期过渡态)对于任何类型的配体都具有较低的能垒,对于较差的σ-给体X和Y配体,能垒会降低,因为它们使Re-C亚烷基键极化,形成Re(+δ)=C(-δ),这有利于与乙烯反应,乙烯本身被金属中心以相反的方式极化。金属环丁烷也是一个三角双锥,顶点是亚烷基和Y配体,并且它通过较差的σ-给体X和Y而稳定。最好的催化剂将具有更平缓的势能面,因此对于X = 良好的σ-给体(烷基)且Y = 较差的σ-给体(基于O的配体)的不对称配体组合可以得到最好的催化剂。这就解释了与均相类似物Re([三键]CMe)(=CHMe)(OR)2相比,负载在二氧化硅上的明确铼亚烷基具有更高的效率。

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