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溶剂H₂O在新戊基和频哪醇重排反应中作用的理论研究

Theoretical study of the role of solvent H2O in neopentyl and pinacol rearrangements.

作者信息

Yamabe Shinichi, Tsuchida Noriko, Yamazaki Shoko

机构信息

Department of Chemistry, Nara University of Education, Takabatake-cho, Nara 630-8528, Japan.

出版信息

J Comput Chem. 2007 Jul 15;28(9):1561-1571. doi: 10.1002/jcc.20690.

Abstract

The neopentyl and the pinacol rearrangements as examples of Wagner-Meerwein rearrangements were investigated by the use of DFT calculations. As the first reaction, a model of neopentyl chloride (1b) and (H2O)12 was employed. In the reaction, the patterns of C--Cl scission, methyl migration, and C--OH formation were analyzed. The calculations have shown that the 2-methyl-2-butanol (6) is formed in two steps with the transient intermediate, neopentyl alcohol (3). The first step is the nucleophilic substitution reaction and is the rate-determining one. The second step is the dual migration of methyl and OH2 groups. The primary and tertiary carbocations were calculated to be absent in the neopentyl rearrangement starting from the hydrolysis. As the second reaction, the pinacol rearrangement of two substrates 2,3-dimethyl-2,3-butanediol (7) and 2,3-diphenyl-2,3-butanediol (12) was investigated. Acidic aqueous solvent was modeled by H3O+ and 12H2O. The reaction paths were promoted by a hydrogen-bond circuit of H3O+(H2O)2 and were determined as completely concerted processes. Protonated species and carbocations as intermediates also do not intervene during the pinacol rearrangement. Active functions of proton relays along the hydrogen bonds in the two rearrangements were demonstrated.

摘要

通过密度泛函理论(DFT)计算研究了作为瓦格纳-米尔温重排实例的新戊基重排和频哪醇重排。作为第一个反应,采用了新戊基氯(1b)和(H₂O)₁₂的模型。在该反应中,分析了C-Cl键断裂、甲基迁移和C-OH形成的模式。计算结果表明,2-甲基-2-丁醇(6)是通过瞬态中间体新戊醇(3)分两步形成的。第一步是亲核取代反应,也是速率决定步骤。第二步是甲基和OH₂基团的双重迁移。从水解开始的新戊基重排中计算得出不存在伯碳正离子和叔碳正离子。作为第二个反应,研究了两种底物2,3-二甲基-2,3-丁二醇(7)和2,3-二苯基-2,3-丁二醇(12)的频哪醇重排。酸性水溶剂由H₃O⁺和12H₂O模拟。反应路径由H₃O⁺(H₂O)₂的氢键回路促进,并被确定为完全协同的过程。质子化物种和碳正离子作为中间体在频哪醇重排过程中也不介入。证明了在这两种重排中沿氢键的质子传递的活性作用。

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