Macías Ramón, Bould Jonathan, Holub Josef, Kennedy John D, Stíbr Bohumil, Thornton-Pett Mark
School of Chemistry, University of Leeds, Leeds, UKLS2 9JT.
Dalton Trans. 2007 Jul 21(27):2885-97. doi: 10.1039/b702767b. Epub 2007 May 1.
Reaction between [RhCl(PPh(3))(3)] and the nido-6-NB(9)H(11) anion in CH(2)Cl(2) yields orange eleven-vertex [8,8-(PPh(3))(2)-nido-8,7-RhNB(9)H(11)]. Reaction of the nido-6-CB(9)H(12) anion with [cis-PtCl(2)(PMe(2)Ph)(2)] in methanol affords yellow eleven-vertex [9-(OMe)-8,8-(PMe(2)Ph)(2)-nido-8,7-PtCB(9)H(10)], which is also formed from the reaction of MeOH with [8,8-(PPh(3))(2)-nido-8,7-PtCB(9)H(10)]. Both compounds have been characterised by single-crystal X-ray diffraction analysis and examined by NMR spectroscopy and have structures based on eleven-vertex nido-type geometries, with the metal centre and the heteroatoms in the adjacent (8)- and (7)-positions on the pentagonal open face. The metal-to-heteroborane bonding sphere of is fluxional, with a DeltaG(double dagger) value of 48.4 kJ mol(-1). DFT calculations on the model compounds [8,8-(PH(3))(2)-nido-8,7-RhNB(9)H(11)] and [8,8-(PH(3))(2)-nido-8,7-RhSB(9)H(10)] have been carried out to define the fluxional process and the intermediates involved.
[RhCl(PPh₃)₃]与[nido-6-NB₉H₁₁]⁻阴离子在二氯甲烷中反应生成橙色的十一个顶点的[8,8-(PPh₃)₂-nido-8,7-RhNB₉H₁₁]。[nido-6-CB₉H₁₂]⁻阴离子与[cis-PtCl₂(PMe₂Ph)₂]在甲醇中反应得到黄色的十一个顶点的[9-(OMe)-8,8-(PMe₂Ph)₂-nido-8,7-PtCB₉H₁₀],它也可由甲醇与[8,8-(PPh₃)₂-nido-8,7-PtCB₉H₁₀]反应形成。这两种化合物均通过单晶X射线衍射分析进行了表征,并通过核磁共振光谱进行了检测,其结构基于十一个顶点的巢式几何形状,金属中心和杂原子位于五角形开放面上相邻的(8)-和(7)-位置。金属与杂硼烷的键合球是可流动的,ΔG(双匕首)值为48.4 kJ mol⁻¹。对模型化合物[8,8-(PH₃)₂-nido-8,7-RhNB₉H₁₁]和[8,8-(PH₃)₂-nido-8,7-RhSB₉H₁₀]进行了密度泛函理论计算,以确定流动过程和所涉及的中间体。