Foti Mario C
Instituto di Chimica Biomolecolare del CNR, Via del Santuario, 110 Valverde (CT) 95028, Italy.
J Pharm Pharmacol. 2007 Dec;59(12):1673-85. doi: 10.1211/jpp.59.12.0010.
The current understanding of the antioxidant properties of phenols (in homogeneous solutions) is reviewed, with particular emphasis on the role of the solvent. Phenols (ArOH) are known to reduce the rates of oxidation of organic matter by transferring a H atom (from their OH groups) to the chain-carrying ROO* radicals, a mechanism that most likely involves a concerted transfer of the hydrogen as a proton and of one electron between the two oxygen atoms, O-H---O* (proton-coupled electron transfer mechanism). The antioxidant capabilities of phenols are strongly reduced by hydrogen-bond accepting solvents since the hydrogen-bonded molecules ArOH---S are virtually unreactive toward ROO* radicals. The magnitude of these kinetic solvent effects is determined by the solute acidity alpha(2)(H) of ArOH (range 0 to 1) and solvent basicity beta(2)(H) (range 0 to 1). Hydroxyl solvents (alcohols) have a double effect on ArOH. On the one hand, they act as hydrogen-bond accepting solvents and reduce the conventional rates of the ArOH + ROO* reaction. On the other hand, these solvents favour the ionization of ArOH into their phenoxide anions ArO(-), which may react with ROO* very rapidly by electron transfer (sequential proton loss electron transfer mechanism). The overall effect is therefore determined by the ionization degree of ArOH. Other aspects of the kinetics and thermodynamics of ArOH + ROO* are also discussed.
本文综述了目前对酚类(在均相溶液中)抗氧化性能的理解,特别强调了溶剂的作用。已知酚类(ArOH)通过将一个氢原子(从其OH基团)转移到链传递ROO自由基上来降低有机物的氧化速率,这种机制很可能涉及氢作为质子以及一个电子在两个氧原子之间的协同转移,即O-H---O(质子耦合电子转移机制)。由于氢键结合的分子ArOH---S对ROO自由基几乎没有反应活性,所以氢键接受型溶剂会大大降低酚类的抗氧化能力。这些动力学溶剂效应的大小由ArOH的溶质酸度α(2)(H)(范围为0至1)和溶剂碱度β(2)(H)(范围为0至1)决定。羟基溶剂(醇类)对ArOH有双重作用。一方面,它们作为氢键接受型溶剂,降低了ArOH + ROO反应的常规速率。另一方面,这些溶剂有利于ArOH离子化为其酚氧阴离子ArO(-),后者可通过电子转移(顺序质子损失电子转移机制)与ROO非常迅速地反应。因此,总体效果取决于ArOH的电离程度。还讨论了ArOH + ROO动力学和热力学的其他方面。