Mendell N R, Thode H C, Finch S J
Department of Applied Mathematics and Statistics, University at Stony Brook, New York 11794.
Biometrics. 1991 Sep;47(3):1143-8.
We find, through simulation and modeling, an approximation to the alternative distribution of the likelihood ratio test for two-component mixtures in which the components have different means but equal variances. We consider the range of mixing proportions from 0.5 through .95. Our simulation results indicate a dependence of power on the mixing proportion when pi less than .2 and pi greater than .80. Our model results indicated that the alternative distribution is approximately noncentral chi-square, possibly with 2 degrees of freedom. Using this model, we estimate a sample of 40 is needed to have 50% power to detect a difference between means equal to 3.0 for mixing proportions between .2 and .8. The sample size increases to 50 when the mixing proportion is .90 (or .1) and 82 when the mixing proportion is .95 (or .05). This paper contains a complete table of sample sizes needed for 50%, 80%, and 90% power.
通过模拟和建模,我们找到了一种近似方法,用于检验两组分混合物似然比检验的备择分布,其中两组分均值不同但方差相等。我们考虑混合比例从0.5到0.95的范围。我们的模拟结果表明,当π小于0.2且π大于0.80时,功效依赖于混合比例。我们的模型结果表明,备择分布近似为非中心卡方分布,可能具有2个自由度。使用该模型,我们估计对于混合比例在0.2到0.8之间的情况,需要40个样本才能有50%的功效检测出均值差为3.0。当混合比例为0.90(或0.1)时,样本量增加到50;当混合比例为0.95(或0.05)时,样本量增加到82。本文包含了50%、80%和90%功效所需样本量的完整表格。