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家禽和牛中微卫星与单核苷酸多态性的信息含量比较。

Comparison of information content for microsatellites and SNPs in poultry and cattle.

作者信息

Schopen G C B, Bovenhuis H, Visker M H P W, van Arendonk J A M

机构信息

Animal Breeding and Genomics Centre, Wageningen University, Wageningen, 6700 AH, The Netherlands.

出版信息

Anim Genet. 2008 Aug;39(4):451-3. doi: 10.1111/j.1365-2052.2008.01736.x. Epub 2008 May 21.

Abstract

Data were available for 12 poultry microsatellites and 29 poultry single nucleotide polymorphisms (SNPs), and for 34 cattle microsatellites and 36 cattle SNPs. Stochastic permutation was used to determine the number of SNPs needed to obtain the same average information content as a given number of microsatellites. For poultry, the information content averaged 0.71 for the 12 microsatellites compared to 0.72 for the 29 SNPs. For cattle, the information content averaged 0.92 for the 34 microsatellites compared with 0.79 for the 36 SNPs. This study shows that, for each microsatellite, three SNPs are needed to obtain the same average information content.

摘要

有12个家禽微卫星和29个家禽单核苷酸多态性(SNP)的数据,以及34个牛微卫星和36个牛SNP的数据。采用随机排列来确定获得与给定数量微卫星相同平均信息含量所需的SNP数量。对于家禽,12个微卫星的信息含量平均为0.71,而29个SNP的信息含量平均为0.72。对于牛,34个微卫星的信息含量平均为0.92,而36个SNP的信息含量平均为0.79。这项研究表明,对于每个微卫星,需要三个SNP才能获得相同的平均信息含量。

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