Toraya Tetsuo, Tamura Naohisa, Watanabe Takeshi, Yamanishi Mamoru, Hieda Naoki, Mori Koichi
Department of Bioscience and Biotechnology, Graduate School of Natural Science and Technology, Okayama University, Tsushima-naka, Okayama, Japan.
J Biochem. 2008 Oct;144(4):437-46. doi: 10.1093/jb/mvn086. Epub 2008 Jun 27.
The reactions of diol dehydratase with 3-unsaturated 1,2-diols and thioglycerol were investigated. Holodiol dehydratase underwent rapid and irreversible inactivation by either 3-butene-1,2-diol, 3-butyne-1,2-diol or thioglycerol without catalytic turnovers. In the inactivation, the Co-C bond of adenosylcobalamin underwent irreversible cleavage forming unidentified radicals and cob(II)alamin that resisted oxidation even in the presence of oxygen. Two moles of 5'-deoxyadenosine per mol of enzyme was formed as an inactivation product from the coenzyme adenosyl group. Inactivated holoenzymes underwent reactivation by diol dehydratase-reactivating factor in the presence of ATP, Mg(2+) and adenosylcobalamin. It was thus concluded that these substrate analogues served as mechanism-based inactivators or pseudosubstrates, and that the coenzyme was damaged in the inactivation, whereas apoenzyme was not damaged. In the inactivation by 3-unsaturated 1,2-diols, product radicals stabilized by neighbouring unsaturated bonds might be unable to back-abstract the hydrogen atom from 5'-deoxyadenosine and then converted to unidentified products. In the inactivation by thioglycerol, a product radical may be lost by the elimination of sulphydryl group producing acrolein and unidentified sulphur compound(s). H(2)S or sulphide ion was not formed. The loss or stabilization of product radicals would result in the inactivation of holoenzyme, because the regeneration of the coenzyme becomes impossible.
研究了二醇脱水酶与3-不饱和1,2-二醇和硫代甘油的反应。全酶形式的二醇脱水酶会被3-丁烯-1,2-二醇、3-丁炔-1,2-二醇或硫代甘油迅速且不可逆地失活,且无催化周转。在失活过程中,腺苷钴胺素的Co-C键发生不可逆断裂,形成未鉴定的自由基和钴胺素(II),即使在有氧存在的情况下,钴胺素(II)也能抵抗氧化。每摩尔酶会形成两摩尔5'-脱氧腺苷,作为辅酶腺苷基团的失活产物。失活的全酶在二醇脱水酶激活因子、ATP、Mg(2+)和腺苷钴胺素存在的情况下会重新激活。因此可以得出结论,这些底物类似物作为基于机制的失活剂或假底物,并且辅酶在失活过程中受损,而脱辅基酶未受损。在被3-不饱和1,2-二醇失活的过程中,由相邻不饱和键稳定的产物自由基可能无法从5'-脱氧腺苷中反萃取氢原子,然后转化为未鉴定的产物。在被硫代甘油失活的过程中,产物自由基可能会通过消除巯基生成丙烯醛和未鉴定的硫化合物而损失。未形成H(2)S或硫离子。产物自由基的损失或稳定会导致全酶失活,因为辅酶的再生变得不可能。