Bojarska Elzbieta, Kazimierczuk Zygmunt, Mouchard Claire, Tfibel Francis, Fontaine-Aupart Marie-Pierre
Department of Biophysics, University of Warsaw, 02-089, Warsaw, Poland.
Photochem Photobiol Sci. 2008 Sep;7(9):1054-62. doi: 10.1039/b805149f. Epub 2008 Jul 24.
The phototransformation of 2-chloro, 6-chloro and 2,6-dichloropurines under UVC excitation (254 nm) has been studied and the major photoproducts have been identified using absorption spectroscopy, HPLC and mass spectrometry. It was shown that hydroxypurines were formed as the main products for all three investigated compounds both in the presence and absence of oxygen. In the case of 6-chloro- and 2,6-dichloropurine, a photodimer is also formed as a minor photoproduct in the absence of oxygen but is efficiently quenched in the presence of oxygen. Nanosecond photolysis experiments also revealed significant intersystem crossing to the triplet state of the chloropurines which has been characterized (transient absorption spectra, triplet formation quantum yields and rate constants of quenching by oxygen, Mn2+ ions and ground state). Experimental evidence allows to conclude that the triplet state is involved in photodimer formation whereas the hydroxypurine is formed from the reaction of the excited singlet state of chloropurines with the solvent (water addition) through heterolytic C-Cl bond rupture. Mass spectrometry and 1H NMR results allowed to propose a chemical pathway for dimer formation in the case of 2,6-dichloropurine in a two-step process: first a homolytic rupture of C-Cl bond in the triplet state of the molecule with the formation of purinyl radicals, which subsequently react with an excess of ground state molecules and/or hydroxypurine primarily formed.
研究了2-氯嘌呤、6-氯嘌呤和2,6-二氯嘌呤在UVC激发(254 nm)下的光转化过程,并利用吸收光谱、高效液相色谱和质谱对主要光产物进行了鉴定。结果表明,无论有无氧气存在,这三种被研究的化合物均以羟基嘌呤作为主要产物。对于6-氯嘌呤和2,6-二氯嘌呤,在无氧条件下会形成一种光二聚体作为次要光产物,但在有氧条件下会被有效淬灭。纳秒光解实验还揭示了氯嘌呤会发生显著的系间窜越至三重态,并且对该三重态进行了表征(瞬态吸收光谱、三重态形成量子产率以及被氧气、Mn2+离子和基态淬灭的速率常数)。实验证据表明,三重态参与了光二聚体的形成,而羟基嘌呤是由氯嘌呤的激发单重态与溶剂(加水反应)通过异裂C-Cl键断裂反应形成的。质谱和1H NMR结果有助于提出2,6-二氯嘌呤形成二聚体的两步化学途径:首先分子的三重态中C-Cl键发生均裂形成嘌呤基自由基,随后这些自由基主要与过量的基态分子和/或最初形成的羟基嘌呤发生反应。