Vyazmensky Maria, Zherdev Yuri, Slutzker Alex, Belenky Inna, Kryukov Olga, Barak Ze'ev, Chipman David M
Department of Life Sciences, Ben-Gurion University of the Negev, Beer-Sheva 84105, Israel.
Biochemistry. 2009 Sep 15;48(36):8731-7. doi: 10.1021/bi9009488.
The large, catalytic subunits (LSUs; ilvB, ilvG and ilvI, respectively) of enterobacterial acetohydroxyacid synthases isozymes (AHAS I, II and III) have molecular weights approximately 60 kDa and are paralogous with a family of other thiamin diphosphate dependent enzymes. The small, regulatory subunits (SSUs) of AHAS I and AHAS III (ilvN and ilvH) are required for valine inhibition, but ilvN and ilvH can only confer valine sensitivity on their own LSUs. AHAS II is valine resistant. The LSUs have only approximately 15, <<1 and approximately 3%, respectively, of the activity of their respective holoenzymes, but the holoenzymes can be reconstituted with complete recovery of activity. We have examined the activation of each of the LSUs by SSUs from different isozymes and ask to what extent such activation is specific; that is, is effective nonspecific interaction possible between LSUs and SSUs of different isozymes? To our surprise, the AHAS II SSU ilvM is able to activate the LSUs of all three of the isozymes, and the truncated AHAS III SSUs ilvH-Delta80, ilvH-Delta86 and ilvH-Delta89 are able to activate the LSUs of both AHAS I and AHAS III. However, none of the heterologously activated enzymes have any feedback sensitivity. Our results imply the existence of a common region in all three LSUs to which regulatory subunits may bind, as well as a similarity between the surfaces of ilvM and the other SSUs. This surface must be included within the N-terminal betaalphabetabetaalphabeta-domain of the SSUs, probably on the helical face of this domain. We suggest hypotheses for the mechanism of valine inhibition, and reject one involving induced dissociation of subunits.
肠杆菌乙酰羟酸合酶同工酶(AHAS I、II和III)的大型催化亚基(LSU;分别为ilvB、ilvG和ilvI)分子量约为60 kDa,与其他硫胺素二磷酸依赖性酶家族是旁系同源的。AHAS I和AHAS III(ilvN和ilvH)的小型调节亚基(SSU)是缬氨酸抑制所必需的,但ilvN和ilvH只能使其自身的LSU具有缬氨酸敏感性。AHAS II对缬氨酸具有抗性。LSU各自的全酶活性分别仅约为15%、远低于1%和约3%,但全酶可以重新组装并完全恢复活性。我们研究了不同同工酶的SSU对每个LSU的激活作用,并询问这种激活在多大程度上具有特异性;也就是说,不同同工酶的LSU和SSU之间是否可能发生有效的非特异性相互作用?令我们惊讶的是,AHAS II的SSU ilvM能够激活所有三种同工酶的LSU,截短的AHAS III的SSU ilvH-Delta80、ilvH-Delta86和ilvH-Delta89能够激活AHAS I和AHAS III的LSU。然而,任何异源激活的酶都没有任何反馈敏感性。我们的结果表明,所有三个LSU中存在一个调节亚基可能结合的共同区域,以及ilvM和其他SSU表面之间的相似性。这个表面必须包含在SSU的N端β-α-β-α-β结构域内,可能在该结构域的螺旋面上。我们提出了缬氨酸抑制机制的假设,并否定了一个涉及亚基诱导解离的假设。