Institut des Sciences et Ingénierie Chimiques, Ecole Polytechnique Fédérale de Lausanne, CH-1015 Lausanne, Switzerland.
J Phys Chem A. 2009 Oct 29;113(43):11888-97. doi: 10.1021/jp903237w.
The reaction of the anticancer compound (eta(6)-benzene)Ru(en)(OH(2)) (1) toward the nucleobases guanine, adenine, and cytosine is studied computationally using DFT/BP86 calculations. The aqua leaving group of such compounds is known to undergo ligand exchange reactions with nucleophilic centers in DNA and preferentially with the N7 atom of guanine, N7(G). Our results show that an H-bonded reactant adduct with nucleobases is formed via either the aqua ligand (cis adduct) or the en (ethylenediamine) ligand (trans adduct) of 1. All studied nucleobases favor an H-bonded cis adduct. Only guanine forms also a trans reactant adduct in the gas phase. The guanine N7 and O6 atoms in this trans adduct are situated in an ideal position to form each a strong H-bond to both amino groups of the en ligand of 1. A docking study shows that this unique recognition pattern is also plausible for the interaction with double stranded DNA. For the reaction of 1 with guanine, we identified three different reaction pathways: (i) A cis (G)N7-Ru-OH(2) transition state (TS). (ii) A direct trans reaction pathway. (iii) A 2-step trans mechanism. The activation energies for the cis pathway are smaller than for the trans pathways. The ultimately formed Ru-N7(G) product is characterized by a thermally stable H-bond between the O6(G) and a diamine-NH(2) hydrogen.
(η(6)-苯)Ru(en)(OH(2))(1)抗癌化合物与鸟嘌呤、腺嘌呤和胞嘧啶等碱基的反应通过 DFT/BP86 计算进行了计算研究。已知此类化合物的水离去基团会与 DNA 中的亲核中心发生配体交换反应,并优先与鸟嘌呤的 N7 原子(N7(G))发生反应。我们的结果表明,通过 1 的水配体(顺式加合物)或乙二胺(en)配体(反式加合物)形成与碱基形成氢键的反应物加合物。所有研究的碱基都有利于氢键的顺式加合物。只有在气相中,鸟嘌呤也会形成反式反应物加合物。在该反式加合物中,鸟嘌呤的 N7 和 O6 原子位于理想位置,能够与 1 的 en 配体的两个氨基基团形成每个强氢键。对接研究表明,这种独特的识别模式对于与双链 DNA 的相互作用也是合理的。对于 1 与鸟嘌呤的反应,我们确定了三种不同的反应途径:(i)顺式(G)N7-Ru-OH(2)过渡态(TS)。(ii)直接反式反应途径。(iii)两步反式机制。顺式途径的活化能小于反式途径。最终形成的 Ru-N7(G)产物的特点是 O6(G)和二胺-NH(2)氢之间存在热稳定的氢键。