Endocrinology Department, Faculty of Medicine, Pontificia Universidad Catolica de Chile, Santiago, Chile.
J Endocrinol Invest. 2011 Feb;34(2):140-4. doi: 10.1007/BF03347044. Epub 2010 Jul 13.
Familial hyperaldosteronism type I (FH-I) is an autosomal dominant disorder caused by an unequal cross-over of the gene encoding steroid 11β-hydroxylase (CYP11B1) and aldosterone synthase (CYP11B2), giving rise to a chimeric CYP11B1/CYP11B2 gene that displays aldosterone synthase activity regulated by ACTH instead of angiotensin II.
To report an unprecedented case of a de novo unequal crossover mutation between CYP11B1 and CYP11B2 genes causing FH-I.
The index case is a 45-yr-old Chilean male diagnosed with primary aldosteronism (PA). All family members were also studied: his biological parents, 1 brother, 6 sisters, 2 daughters, and 1 son. Plasma renin activity, serum aldosterone, and its ratio were measured in all patients. Genetic analyses were performed using long-extension PCR (XL-PCR), DNA sequencing and Southern blot methods.
PA was diagnosed for the index case, 1 of his daughters, his son but not for his parents or siblings. XLPCR and Southern blotting demonstrated the presence of the chimeric CYP11B1/CYP11B2 gene solely in PA-affected subjects, suggesting a case of a de novo mutation. Sequence analysis showed the unequal cross-over CYP11B1/CYP11B2 at intron 2 (c.2600-273 CYP11B2). We also identified a polymorphism at the same intron (c.2600-145C>A CYP11B2) in the genome of the index case's father.
We describe an unprecedented case of unequal cross-over mutation for the chimeric CYP11B1/CYP11B2 gene causing FH-I, which may be linked to a polymorphism in the index case's father germ line.
家族性醛固酮增多症 I 型(FH-I)是一种常染色体显性遗传病,由编码类固醇 11β-羟化酶(CYP11B1)和醛固酮合酶(CYP11B2)的基因不等交叉引起,导致嵌合 CYP11B1/CYP11B2 基因具有受 ACTH 而不是血管紧张素 II 调节的醛固酮合酶活性。
报告 CYP11B1 和 CYP11B2 基因之间前所未有的从头不等交叉突变导致 FH-I 的病例。
指数病例为一名 45 岁智利男性,诊断为原发性醛固酮增多症(PA)。还对所有家庭成员进行了研究:他的亲生父母、1 个兄弟、6 个姐妹、2 个女儿和 1 个儿子。所有患者均测量了血浆肾素活性、血清醛固酮及其比值。使用长延伸 PCR(XL-PCR)、DNA 测序和 Southern 印迹方法进行基因分析。
PA 被诊断为指数病例、他的 1 个女儿、他的儿子,但不是他的父母或兄弟姐妹。XL-PCR 和 Southern 印迹显示仅在 PA 受累患者中存在嵌合 CYP11B1/CYP11B2 基因,提示为从头突变。序列分析显示 CYP11B1/CYP11B2 在第 2 内含子(c.2600-273 CYP11B2)的不等交叉。我们还在指数病例父亲的基因组中发现了同一内含子(c.2600-145C>A CYP11B2)的多态性。
我们描述了一个前所未有的嵌合 CYP11B1/CYP11B2 基因不等交叉突变导致 FH-I 的病例,该突变可能与指数病例父亲的种系多态性有关。