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酿酒酵母中一种不依赖RME1的孢子形成控制途径通过IME1转录物积累发挥作用。

An RME1-independent pathway for sporulation control in Saccharomyces cerevisiae acts through IME1 transcript accumulation.

作者信息

Kao G, Shah J C, Clancy M J

机构信息

Department of Biological Sciences, University of New Orleans, Louisiana 70148.

出版信息

Genetics. 1990 Dec;126(4):823-35. doi: 10.1093/genetics/126.4.823.

Abstract

The RES1-1 mutation was isolated on the basis of its ability to allow MATa/MAT alpha diploid Saccharomyces cerevisiae cells to express a late sporulation-regulated gene, SPR3, in the presence of excess copies of RME1. RME1 is a repressor of meiosis that is normally expressed in cells that lack the a1/alpha 2 repressor encoded by MAT. The RES1-1 mutation also supports sporulation in mat-insufficient diploids. This phenotype does not result from a failure to express RME1 and is not due to activation of the silent copies of mating type information. RES1-1 activates sporulation by allowing IME1 accumulation in all cell types, irrespective of the presence of the MAT products. IME1 is still responsive to RME1 in RES1-1 cells, since double mutants (rme1 RES1-1) that are deficient at MAT can sporulate better than either single mutant. RES1-1 is not an allele of IME1.

摘要

RES1-1突变是根据其使MATa/MATα二倍体酿酒酵母细胞在存在过量RME1拷贝的情况下表达晚期孢子形成调控基因SPR3的能力而分离出来的。RME1是减数分裂的一种阻遏物,通常在缺乏由MAT编码的a1/α2阻遏物的细胞中表达。RES1-1突变也支持mat缺陷二倍体的孢子形成。这种表型不是由于未能表达RME1,也不是由于交配型信息沉默拷贝的激活。RES1-1通过允许IME1在所有细胞类型中积累来激活孢子形成,而不管MAT产物的存在与否。在RES1-1细胞中,IME1仍然对RME1有反应,因为在MAT处存在缺陷的双突变体(rme1 RES1-1)比任何一个单突变体都能更好地形成孢子。RES1-1不是IME1的等位基因。

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Meiosis in haploid yeast.单倍体酵母中的减数分裂。
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