Department of Biological Sciences, University of Calgary, Calgary, AB T2N 1N4, Canada.
Biochem Cell Biol. 2010 Oct;88(5):861-9. doi: 10.1139/O10-009.
The Met-542 residue of β-galactosidase is important for the enzyme's activity because it acts as a guide for the movement of the benzyl side chain of Phe-601 between two stable positions. This movement occurs in concert with an important conformational change (open vs. closed) of an active site loop (residues 794-803). Phe-601 and Arg-599, which interact with each other via the π electrons of Phe-601 and the guanidium cation of Arg-599, move out of their normal positions and become disordered when Met-542 is replaced by an Ala residue because of the loss of the guide. Since the backbone carbonyl of Phe-601 is a ligand for Na(+), the Na(+) also moves out of its normal position and becomes disordered; the Na(+) binds about 120 times more poorly. In turn, two other Na(+) ligands, Asn-604 and Asp-201, become disordered. A substrate analog (IPTG) restored Arg-599, Phe-601, and Na(+) to their normal open-loop positions, whereas a transition state analog d-galactonolactone) restored them to their normal closed-loop positions. These compounds also restored order to Phe-601, Asn-604, Asp-201, and Na(+). Binding energy was, however, necessary to restore structure and order. The K(s) values of oNPG and pNPG and the competitive K(i) values of substrate analogs were 90-250 times higher than with native enzyme, whereas the competitive K(i) values of transition state analogs were ~3.5-10 times higher. Because of this, the E•S energy level is raised more than the E•transition state energy level and less activation energy is needed for galactosylation. The galactosylation rates (k₂) of M542A-β-galactosidase therefore increase. However, the rate of degalactosylation (k₃) decreased because the E•transition state complex is less stable.
β-半乳糖苷酶的 Met-542 残基对于酶的活性很重要,因为它充当苯丙氨酸 601 的苄基侧链在两个稳定位置之间移动的指南。这种运动与活性位点环(残基 794-803)的重要构象变化(开与闭)同时发生。苯丙氨酸 601 和精氨酸 599 通过苯丙氨酸 601 的π电子和精氨酸 599 的胍阳离子相互作用,当 Met-542 被丙氨酸残基取代时,由于失去了引导,它们会离开正常位置并变得无序。由于苯丙氨酸 601 的骨架羰基是 Na+的配体,因此 Na+也会离开其正常位置并变得无序;Na+的结合能力降低约 120 倍。反过来,另外两个 Na+配体,天冬酰胺 604 和天冬氨酸 201,也变得无序。底物类似物(IPTG)将精氨酸 599、苯丙氨酸 601 和 Na+恢复到正常的开环位置,而过渡态类似物 d-半乳糖内酯则将它们恢复到正常的闭环位置。这些化合物还使苯丙氨酸 601、天冬酰胺 604、天冬氨酸 201 和 Na+恢复有序。然而,需要结合能来恢复结构和有序性。oNPG 和 pNPG 的 K(s)值以及底物类似物的竞争性 K(i)值比天然酶高 90-250 倍,而过渡态类似物的竞争性 K(i)值高 3.5-10 倍。因此,E•S 能级的升高超过了 E•过渡态能级的升高,并且需要更少的活化能进行半乳糖基化。因此,M542A-β-半乳糖苷酶的半乳糖基化速率(k₂)增加。然而,由于 E•过渡态复合物不太稳定,去半乳糖基化速率(k₃)降低。