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在 193nm 下环戊酮和环己酮肟中 N-OH 键离解的动力学:新生 OH(v'',J'')的激光诱导荧光检测。

Dynamics of N-OH bond dissociation in cyclopentanone and cyclohexanone oxime at 193 nm: laser-induced fluorescence detection of nascent OH (v'', J'').

机构信息

Radiation and Photochemistry Division, Bhabha Atomic Research Centre, Trombay, Mumbai-400 085, India.

出版信息

J Phys Chem A. 2010 Dec 2;114(47):12369-77. doi: 10.1021/jp104095v. Epub 2010 Nov 8.

Abstract

Cyclohexanone oxime (CHO) and cyclopentanone oxime (CPO) in the vapor phase undergo N-OH bond scission upon excitation at 193 nm to produce OH, which was detected state selectively employing laser-induced fluorescence. The measured energy distribution between fragments for both oximes suggests that in CHO the OH produced is mostly vibrationally cold, with moderate rotational excitation, whereas in CPO the OH fragment is also formed in v'' = 1 (~2%). The rotational population of OH (v'' = 0, J'') from CHO is characterized by a rotational temperature of 1440 ± 80 K, whereas the rotational populations of OH (v'' = 0, J'') and OH (v'' = 1, J'') from CPO are characterized by temperatures of 1360 ± 90 K and 930 ± 170 K, respectively. A high fraction of the available energy is partitioned to the relative translation of the fragments with f(T) values of 0.25 and 0.22 for CHO and CPO, respectively. In the case of CHO, the Λ-doublet states of the nascent OH radical are populated almost equally in lower rotational quantum levels N'', with a preference for Π(+) (A') states for higher N''. However, there is no preference for either of the two spin orbit states Π(3/2) and Π(1/2) of OH. The nascent OH product in CPO is equally distributed in both Λ-doublet states of Π(+) (A') and Π(-) (A'') for all N'', but has a preference for the Π(3/2) spin orbit state. Experimental work in combination with theoretical calculations suggests that both CHO and CPO molecules at 193 nm are excited to the S(2) state, which undergoes nonradiative relaxation to the T(2) state. Subsequently, molecules undergo the N-OH bond dissociation from the T(2) state with an exit barrier to produce OH (v'', J'').

摘要

环己酮肟(CHO)和环戊酮肟(CPO)在气相中,在 193nm 激发下,N-OH 键断裂产生 OH,这是通过激光诱导荧光选择性检测到的。对于两种肟,所测量的碎片之间的能量分布表明,在 CHO 中,产生的 OH 主要是振动冷的,具有中等的旋转激发,而在 CPO 中,OH 碎片也以 v''=1(~2%)的形式形成。CHO 产生的 OH(v''=0,J'')的旋转布居由 1440±80K 的旋转温度来表征,而 CPO 产生的 OH(v''=0,J'')和 OH(v''=1,J'')的旋转布居由 1360±90K 和 930±170K 的温度来表征。大量的可用能量分配给碎片的相对平移,f(T)值分别为 CHO 和 CPO 的 0.25 和 0.22。在 CHO 的情况下,新生 OH 自由基的 Λ-双重态几乎以相等的概率分布在较低的旋转量子能级 N''中,对于较高的 N'',优先选择 Π(+)(A')态。然而,OH 没有优先选择两种自旋轨道态 Π(3/2)和 Π(1/2)。CPO 中的新生 OH 产物在所有 N''中,在 Π(+)(A')和 Π(-)(A'')的两个 Λ-双重态中均匀分布,但优先选择 Π(3/2)自旋轨道态。实验工作与理论计算相结合表明,在 193nm 处,CHO 和 CPO 分子都被激发到 S(2)态,随后通过非辐射弛豫到 T(2)态。随后,分子从 T(2)态通过出口势垒经历 N-OH 键断裂,产生 OH(v'',J'')。

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