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关于脂氧合酶的单一或双重位置特异性。手性产物的数量随酶活性位点处亚甲基的排列而变化。

On singular or dual positional specificity of lipoxygenases. The number of chiral products varies with alignment of methylene groups at the active site of the enzyme.

作者信息

Kühn H, Sprecher H, Brash A R

机构信息

Division of Clinical Pharmacology, School of Medicine, Vanderbilt University, Nashville, Tennessee 37232-6602.

出版信息

J Biol Chem. 1990 Sep 25;265(27):16300-5.

PMID:2118902
Abstract

We tested a simple model which explains the singular or dual specificity of lipoxygenases. The dual specificity considered here is typified by the oxygenation of arachidonic acid by the reticulocyte lipoxygenase: two chiral products are formed (12S- and 15S-hydroperoxides, ratio approximately 1:9) via hydrogen abstraction from two separate methylene groups (C-10 and C-13). The rate-limiting step is known to involve this hydrogen abstraction, and we assumed that alignment of the methylenes with the hydrogen acceptor on the enzyme is critical in terms of reaction rate and positional specificity. Optimal alignment will be associated with a fast rate of reaction and formation of a single chiral product. A shift in position of the double bonds (and hence of the methylene groups) should be associated with a slower rate of reaction and formation of two chiral products; two methylenes are now able to react, although neither has perfect alignment. We tested this idea using two lipoxygenases and polyenoic fatty acids differing in the number and position of the double bonds. Optimal substrates for the soybean lipoxygenase had a doubly allylic methylene in the n-8 position, while the reticulocyte enzyme preferred substrates with a n-9 methylene. These substrates were converted to a single chiral product. With both enzymes, the other series of substrates reacted more slowly and were converted to two chiral products. We conclude that alignment of methylene groups of the substrate at the active site is a major determinant of the reaction rate and the singular or dual specificity of lipoxygenases.

摘要

我们测试了一个解释脂氧合酶单一或双重特异性的简单模型。这里所考虑的双重特异性以网织红细胞脂氧合酶对花生四烯酸的氧化为典型:通过从两个不同的亚甲基(C-10和C-13)上夺取氢形成两种手性产物(12S-和15S-氢过氧化物,比例约为1:9)。已知限速步骤涉及这种氢的夺取,并且我们假定亚甲基与酶上的氢受体的排列对于反应速率和位置特异性至关重要。最佳排列将与快速的反应速率和单一手性产物的形成相关。双键(以及因此亚甲基)位置的移动应与较慢的反应速率和两种手性产物的形成相关;现在两个亚甲基都能够反应,尽管两者都没有完美排列。我们使用两种脂氧合酶和双键数量及位置不同的多烯脂肪酸来测试这一想法。大豆脂氧合酶的最佳底物在n-8位有一个双烯丙基亚甲基,而网织红细胞酶更喜欢具有n-9亚甲基的底物。这些底物被转化为单一手性产物。对于这两种酶,另一系列底物反应较慢并被转化为两种手性产物。我们得出结论,底物的亚甲基在活性位点的排列是脂氧合酶反应速率以及单一或双重特异性的主要决定因素。

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