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二水合双(2-溴苯甲酸根-κO)双(N,N-二乙基烟酰胺-κN)锌(II)

Diaqua-bis(2-bromo-benzoato-κO)bis-(N,N-diethyl-nicotinamide-κN)zinc(II).

作者信息

Hökelek Tuncer, Dal Hakan, Tercan Barış, Ozbek F Elif, Necefoğlu Hacali

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2009 Apr 2;65(Pt 5):m481-2. doi: 10.1107/S160053680901191X.

DOI:10.1107/S160053680901191X
PMID:21583735
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC2977549/
Abstract

In the centrosymmetric title complex, [Zn(C(7)H(4)BrO(2))(2)(C(10)H(14)N(2)O)(2)(H(2)O)(2)], the Zn(II) atom is located on an inversion center. The asymmetric unit contains one 2-bromo-benzoate (BB), one diethyl-nicotinamide (DENA) ligand and one coordinating water molecule. The four O atoms in the equatorial plane around the Zn atom form a slightly distorted square-planar arrangement, while the slightly distorted octa-hedral coordination is completed by the two N atoms of the DENA ligands in the axial positions. The dihedral angle between the carboxyl group and the adjacent benzene ring is 85.51 (12)°, while the pyridine and benzene rings are oriented at a dihedral angle of 44.07 (6)°. In the crystal structure, O-H⋯O hydrogen bonds link the mol-ecules into infinite chains.

摘要

在中心对称的标题配合物[Zn(C₇H₄BrO₂)₂(C₁₀H₁₄N₂O)₂(H₂O)₂]中,Zn(II)原子位于对称中心上。不对称单元包含一个2-溴苯甲酸根(BB)、一个二乙烟酰胺(DENA)配体和一个配位水分子。围绕Zn原子的赤道平面上的四个O原子形成略微扭曲的平面正方形排列,而轴向位置的DENA配体的两个N原子则完成了略微扭曲的八面体配位。羧基与相邻苯环之间的二面角为85.51 (12)°,而吡啶环和苯环的二面角为44.07 (6)°。在晶体结构中,O—H⋯O氢键将分子连接成无限链。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/433f/2977549/5ef033206188/e-65-0m481-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/433f/2977549/5ef033206188/e-65-0m481-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/433f/2977549/5ef033206188/e-65-0m481-fig1.jpg

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