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叠氮基-{2-[双-(2-羟基-乙基)氨基]-乙醇酸根-κN,O,O',O''}钴(II)

Azido-{2-[bis-(2-hy-droxy-eth-yl)amino]-ethano-lato-κN,O,O',O''}cobalt(II).

作者信息

Liu Yan-Ju, Yang Huai-Xia, Yuan Juan, Wang Xia

机构信息

Pharmacy College, Henan University of Traditional Chinese Medicine, Zhengzhou 450008, People's Republic of China.

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2010 Nov 20;66(Pt 12):m1617. doi: 10.1107/S1600536810047100.

DOI:10.1107/S1600536810047100
PMID:21589293
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC3011546/
Abstract

In the title complex, [Co(C(6)H(14)NO(3))(N(3))] or [Co(teaH(2))N(3)], the Co(II) atom resides in a trigonal-bipymidal O(3)N(2) environment formed by three O atoms and one N atom from a simply deprotonated tetra-dentate triethano-lamine ligand, and one N atom from an azide ligand. The O atoms define the equatorial plane whereas both N atoms are in axial positions. The mononuclear units are linked through O-H⋯O hydrogen-bonding inter-actions between the ethanol OH groups and the ethano-late O atom of a neighbouring complex into chains running parallel to [010].

摘要

在标题配合物[Co(C₆H₁₄NO₃)(N₃)] 或 [Co(teaH₂)N₃]中，Co(II) 原子处于由一个单去质子化的四齿三乙醇胺配体的三个O原子和一个N原子以及一个叠氮配体的一个N原子形成的三角双锥O₃N₂环境中。O原子定义了赤道平面，而两个N原子处于轴向位置。单核单元通过乙醇OH基团与相邻配合物的乙醇酸O原子之间的O-H⋯O氢键相互作用连接成平行于[010]的链。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/a16b/3011546/86fd86e84454/e-66-m1617-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/a16b/3011546/3ecdb6ef2cb1/e-66-m1617-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/a16b/3011546/86fd86e84454/e-66-m1617-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/a16b/3011546/3ecdb6ef2cb1/e-66-m1617-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/a16b/3011546/86fd86e84454/e-66-m1617-fig2.jpg

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本文引用的文献

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